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Reika [66]
3 years ago
5

PLS HELP. Find the value of each variable.

Mathematics
2 answers:
murzikaleks [220]3 years ago
8 0

6. x=100

7.x=75

8.x=30

10.x=112

11.x=58 y=58

luda_lava [24]3 years ago
3 0

Answer:

6) x = 70°

7) x = 75°

8) x = 30°

10) x = 112°

11) x = 58° , y = 58°

Step-by-step explanation:

6) two congruent sides means two congruent angles

   x + x + 40 = 180         2x = 140

7) two congruent sides means two congruent angles

   both base angles measure 75 degrees

8) isosceles triangle (has two equal sides)   75(2) + x = 180    150 + x = 180

10)  two congruent angles means two congruent sides

      44 + 2n = 180      2n = 136      n = 68

      angles n and x form a linear pair and equal 180

      180 - 68 = 112

11) isosceles triangle so ∡x = ∡y   64 + x + x = 180

   64 + 2x = 180      2x = 116        x = 58

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8 0
3 years ago
Each variable indicates different weights. Which weight can you find? Find it.
SOVA2 [1]

Answer:

We can only be certain that <em>a</em> weighs 12.

There are infinitely many possiblities for <em>b</em> and <em>c</em>.

Step-by-step explanation:

We have the equation:

a+b+c+a+c+b+a+c=12+a+a+b+b+c+c+c

Each variable indicates a weight.

We would like to determine the weights of each variable (if possible).

First, we can rearrange the equation to acquire:

(a+a+a)+(b+b)+(c+c+c)=12+(a+a)+(b+b)+(c+c+c)

We can combine like terms:

3a+2b+3c=12+2a+2b+3c

Notice that both sides have 2<em>b</em> and 3<em>c</em>. Therefore, it is possible for us to cancel them since each nullify the other side. So, we will subtract 2<em>b</em> and 3<em>c</em> from both sides. This yields:

3a=12+2a

Therefore, we can solve for <em>a</em>. Subtract 2<em>a</em> from both sides:

a=12

Hence, the weight of <em>a</em> is 12.

Using the newly acquired information, we can go back to our simplified equation:

3a+2b+3c=12+2a+2b+3c

Since <em>a</em> is 12:

3(12)+2b+3c=12+2(12)+2b+3c

Evaluate:

36+2b+3c=12+24+2b+3c

Simplify:

36+2b+3c=36+2b+3c

We can subtract 36 from both sides:

2b+3c=2b+3c

As you can see, this is a true statement.

Since this is a true statement, there are infinitely many possible values for <em>b</em> and <em>c</em>.

Therefore, the only weight we are <em>certain</em> of knowing is weight <em>a</em> weighing 12.

8 0
3 years ago
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