Answer:
The length = 20
The width = 12
Explanation:
Let the Length of the garden be L and the Width W
Therefore the area of the garden = L*W
But we know that L = W + 8
Therefore the area of the garden can be expressed as W*(W + 8)
When the brackets are expanded this equals W^2 + 8W
The area of the recctangle which includes the path and garden will have a length of L + 8 (ie the length of the garden + 4 feet at the top and 4 feet at the bottom)
The width will be W + 8 (width of garden + 4 feet at the left and 4 feet at the right)
Therefore the area will be (W + 8)*(L +8)
Once again we know that L = W + 8
Therefore the area of the path/garden = (W +8)(W +8 +8)
=(W +8)(W +16)
=W^2 +24W + 128
We know that the path alone has an area of 320 square feet. Therefore if we subtract the area of the garden (W^2 + 8W) from the area of the path/garden the area left is the area of the path only
Therefore W^2 + 24W + 128 - (W^2 + 8W) = 320
W^2 + 24W + 128 - W^2 - 8W = 320
Simplify
16W + 128 = 320
Subtract 128 from both sides of the equation
16W = 192
divide both sides of the equation by 16
W = 12
As L = W + 8
L = 12 + 8 = 20
No method can prove that the Triangles are congruent .-.
Answer:
Here's the answers
Step-by-step explanation:
1. When two variables are in relation with a formula or a variable is related by the sum of two or more variables, then it is a partial variation. X = KY + C (where K and C are constants) is a straight line equation which is an example of partial variation.
2. The formula y=kxn y = k x n is used for direct variation. The value k is a nonzero constant greater than zero and is called the constant of variation.
