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gizmo_the_mogwai [7]
4 years ago
7

POLYGONS ABCD & EFGH ARE SIMILAR. WHAT IS THE PERIMETER OF EFGH WHEN AD = 12, BC = 8, FE = 15, FG = 10, and GH = 5?

Mathematics
1 answer:
Lunna [17]4 years ago
8 0
Since two polygons are similar,  the scale factor is FG/BC = 10/8 = 5/4

Which means that the same scale factors applies to other sides as well. Therefore, EH/AD = 5/4
EH =  5/4 * AD =  5/4 *12 = x

Hope this helps
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Step-by-step explanation:

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Can u please answer this question
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We can change the mixed number to a decimal for comparing.

1\frac{1}{4} m = \frac{5}{4} m = 1.25 m

1.4 m     >    1.25 m
Darren   >     Luke

Darren's jump was higher by (1.4-1.25) 0.15 m

Or another way change the decimal to a fraction and the mixed to an improper fraction too.

1\frac{1}{4} = \frac{5}{4} (Luke)
1.4 = \frac{7}{5}                               (Darren)
We need a common denominator to compare
\frac{5*5}{4*5}       (Luke)
\frac{7*4}{5*4}       (Darren)
\frac{25}{20}          (Luke)
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\frac{28}{20}  >   \frac{25}{20}
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By:
\frac{28}{20} - \frac{25}{20} = \frac{3}{20}
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or,110+15+30+b=180

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answer is second one

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