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natka813 [3]
3 years ago
5

what are the main technologies that have contributed to the growth and commercialization of the internet .​

Computers and Technology
1 answer:
harina [27]3 years ago
6 0

Answer:

Explanation: <em>T</em><em>he main forces that led to the commercialization of the internet are its demand and the importance of the Internet.</em>

<em>TCP and IP technologies allowed for the connection of many networks to form on large network. This tech used packets and provided error-recovery mechanisms. Hence many small networks were combined to form the internet.</em>

<em />

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Which of the following is the best way to add a lengthy explanation to Excel data without being limited to cell sizes and restri
trapecia [35]

Answer:

B

Explanation:

Which of the following is the best way to add a lengthy explanation to Excel data without being limited to cell sizes and restrictions? A. Adding a chart object B. Adding an Access object C. Adding a Word object D. Adding an Excel object microsoft word

Answer: B

6 0
3 years ago
You have a computer at home. The computer is connected to the Internet through a dial-up connection. Every time you connect to t
worty [1.4K]

Hiya!

When you connect to the internet (especially through a dial-up connection), your computer must make the request for network resources. This is usually done through a Modem, a device designed to establish and split the connection among your devices.

Fun fact; a dial up connection uses the same radio frequencies that you would use to talk on the phone; and they're in the audible spectrum. When you start up that connection, the reason all those funny noises happen is because it's "talking" to your ISP over those lines.

Hope this helps!

3 0
3 years ago
g write a recursive function that prints out all the even numbers between x and y inclusive if x is odd then the print out will
Reil [10]

Answer:

The function written in python is as follows:

def EvenNumbers(x, y):

    if (y < x):

         return

    if (y % 2 == 0):

         EvenNumbers(x, y - 2)

    else:

         EvenNumbers(x, y - 1)

    if (y % 2 == 0):

         print(y)

Explanation:

x represents the lower limit while y represents the upper limit.

So, the recursion will be repeated as long as x <= y

This defines the function

def EvenNumbers(x, y):

This checks if y < x. If yes, the recursion stops execution and return to the main

<em>     if (y < x): </em>

<em>          return </em>

The following if and else condition checks determines the appropriate range of the recursion.

<em>     if (y % 2 == 0): </em>

<em>          EvenNumbers(x, y - 2) </em>

<em>     else: </em>

<em>          EvenNumbers(x, y - 1) </em>

The above takes care of printing starting at x + 1 if x is odd

This checks and prints the even numbers in the range

<em>     if (y % 2 == 0): </em>

<em>          print(y)</em>

<em />

To call the function from main, make use of

EvenNumbers(x, y)

Where x and y are integers

e.g EvenNumbers(2,10), EvenNumbers(1,17), EvenNumbers(3,21)

<em>See attachment</em>

3 0
3 years ago
Write the one Sale method of the GroceryStore class. Method oneSale has one parameter: the name of one product (that a customer
DIA [1.3K]

Answer:

Check the explanation

Explanation:

bool oneSale(string item){

for(int i=0;i<capacity;i++){ // iterate till the capcity of array

if(item==grocerryList[i].name()){ // if name matches

 if(grocerryList[i].getStock()>0){ // and stock is greater than 0

  grocerryList[i].setStock(grocerryList[i].getStock()-1); // subtract 1 from the stock

// or alternate is grocerryList[i].stock= grocerryList[i].stock-1;

 return true; // return true

}

}

else if(item==grocerryList[i].name()){ // if name matches

 if(grocerryList.getStock()==0){ // but stock is empty

 return false; // return falsse

}

}

else{ // means item is not available so there is no need to check stock

return false; // return false

}

}

}

8 0
3 years ago
Modify an array's elements using other elements write a for loop that sets each array element in bonusscores to the sum of itsel
natali 33 [55]
<span>Assuming that the language is C++ and that the following variables exist: bonusscores is an array of some numeric type (float, double, int, etc). nent is an integer indicating how many elements are in bonusscores. Also assuming that the array is 0 based, so legal subscripts range from 0 to nent-1. // Code starts here for(int x = 0; x < (nent-1); ++x) { bonusscores[x] = bonusscores[x] + bonusscores[x+1]; } // Code ends here Thing to note, since the last element isn't modified, the range for the for loop is reduced by 1 so that every element to actually be modified is visited, but the last element isn't. And since each element after modification isn't needed for future modifications, it's safe to change them in situ.</span>
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3 years ago
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