Answer:
A (information technology)
Explanation:
Answer:
- var today = new Date();
- var dateComp = [];
- dateComp[0] = today.getDate();
- dateComp[1] = today.getMonth();
- dateComp[2] = today.getFullYear();
-
- switch(dateComp[1]){
- case 0:
- console.log("Jan " + dateComp[0] + "," + dateComp[2])
- break;
- case 1:
- console.log("Feb " + dateComp[0] + "," + dateComp[2])
- break;
- case 2:
- console.log("Mar " + dateComp[0] + "," + dateComp[2])
- break;
- case 3:
- console.log("Apr " + dateComp[0] + "," + dateComp[2])
- break;
- case 4:
- console.log("May " + dateComp[0] + "," + dateComp[2])
- break;
- case 5:
- console.log("Jun " + dateComp[0] + "," + dateComp[2])
- break;
- case 6:
- console.log("Jul " + dateComp[0] + "," + dateComp[2])
- break;
- case 7:
- console.log("Aug " + dateComp[0] + "," + dateComp[2])
- break;
- case 8:
- console.log("Sept " + dateComp[0] + "," + dateComp[2])
- break;
- case 9:
- console.log("Oct " + dateComp[0] + "," + dateComp[2])
- break;
- case 10:
- console.log("Nov " + dateComp[0] + "," + dateComp[2])
- break;
- case 11:
- console.log("Dec " + dateComp[0] + "," + dateComp[2])
- break;
- }
Explanation:
The solution code is written in JavaScript.
Firstly, create a Date object (Line 1). The date object will automatically capture the current date and time.
Next create an array dateComp to hold the day, month and year (Line 3 -5). We use the getDate method to get current day, getMonth method for current month and getFullYear method for current year.
This is important to note that the getMonth method will return the value range from 0 - 11 with the Jan is represented as 0, Feb is 1 and so forth. Presume we intend to display the date using the format "month day, year", we can create a switch structure to check the month value which is range from 0 to 11. If month value is 0, generate string Jan + current day + "," + current year. We generate the date string based on different switch cases (7 - 44). We shall see the output similar to the date string as shown below:
Apr 12,2020
<h2>Answer:</h2>
<h2>intelligence - centered</h2>
<h2>
Explanation:</h2>
I hope it helps you
Solution:
initial = float(eval(input('Enter the monthly saving amount: ')))
x = (1 + 0.00417)
month_one = initial * x
month_two = (initial + month_one) * x
month_three = (initial + month_two) * x
month_four = (initial + month_three) * x
month_five = (initial + month_four) * x
month_six = (initial + month_five) * x
print('The sixth month value is: '+str(month_six))
Don't forget the saving amount, and initialize the balance with that amount. Inside the loop, work out and add the interest and then add the saving amount for the next month.
balance = 801
for month in range(6):
balance = balance * (1.00417)
print(balance)
If a run-time error appears when you run a macro that has worked in the past, some part of the macro code no longer makes sense to excel, ehere run-time denotes <span> the time during which a program is running</span>
This error occurs while the program is running.
Running<span> out of memorywill results in a </span>run-time error.
