Answer:
Option D is the correct option.
Explanation:
Window dressing is the type of process by which a firm provides the improvement in fundamental or long-run positions and also they develop their basic values. It does not use the assets of the firm to minimize the long-term debt. So, that's why It borrows the long-term debts through retire the short-term debt that maintain the present ratio of the firm.
Technological improvements allow me to have greater access to goods around the world. I can buy instantly and communicate instantly with producers. Technology can also help me to monitor economic trends, both in my country and in my own life. In summary, technology helps to give me more freedom to make economic choices.
On e2020
Networks in small areas are called Local Area Network (LAN). LAN's are in small areas like offices and buildings. Computers close to each other can make up a LAN network with the right equipments. A LAN network is good for doing business.
Explanation:
User Devices. Users of wireless LANs operate a multitude of devices, such as PCs, laptops, and PDAs. ...
Radio NICs. A major part of a wireless LAN includes a radio NIC that operates within the computer device and provides wireless connectivity.
or routers, repeaters, and access points
Answer:
Explanation:
The following code is written in Java. It is a method that calculates the square root of a number as requested. The method first checks with an IF statement if the parameter value is a positive number and then calculates the square root and prints it to the screen. Otherwise, it prints Number must not be negative. A test case has been provided in the main method and the output can be seen in the attached image below.
import java.util.Scanner;
class Brainly {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.print("Enter a number of type double to calculate square root:");
double num = in.nextDouble();
rootPositive(num);
}
public static void rootPositive(double num) {
if (num > 0) {
System.out.println(Math.sqrt(num));
} else {
System.out.println("Number must not be negative.");
}
}
}
