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What is the value of 4(3x + 5) when x = 11?

navik [9.2K]

Answer:

152

Step-by-step explanation:

3(11)= 33

4(33+5)

4(33)=132

4(5)=20

132+20=152

5 0

3 years ago

(4x³-5x+10) ÷ (x+1)

zlopas [31]

Answer:

4x^2 − 4x −1 + 11 / x+1

Step-by-step explanation:

The answer is

4x^2 − 4x −1 + 11 / x+1

4 0

3 years ago

Read 2 more answers

Use matrices and elementary row to solve the following system:

LiRa [457]

I assume the first equation is supposed to be

$5x-3y+2z=13$

and not

$5x-3x+2x=4x=13$

As an augmented matrix, this system is given by

$\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\4&-2&4&12\end{array}\right]$

Multiply through row 3 by 1/2:

$\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\2&-1&2&6\end{array}\right]$

Add -1(row 2) to row 3:

$\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&5&5\end{array}\right]$

Multiply through row 3 by 1/5:

$\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&1&1\end{array}\right]$

Add -2(row 3) to row 1, and add 3(row 3) to row 2:

$\left[\begin{array}{ccc|c}5&-3&0&11\\2&-1&0&4\\0&0&1&1\end{array}\right]$

Add -3(row 2) to row 1:

$\left[\begin{array}{ccc|c}-1&0&0&-1\\2&-1&0&4\\0&0&1&1\end{array}\right]$

Multiply through row 1 by -1:

$\left[\begin{array}{ccc|c}1&0&0&1\\2&-1&0&4\\0&0&1&1\end{array}\right]$

Add -2(row 1) to row 2:

$\left[\begin{array}{ccc|c}1&0&0&1\\0&-1&0&2\\0&0&1&1\end{array}\right]$

Multipy through row 2 by -1:

$\left[\begin{array}{ccc|c}1&0&0&1\\0&1&0&-2\\0&0&1&1\end{array}\right]$

The solution to the system is then

$\boxed{x=1,y=-2,z=1}$

5 0

3 years ago

It costs $3.45 to buy 3/4 lb of chopped walnuts. How much would it cost to purchase 12 lbs of walnuts? Enter the numeric value o

mote1985 [20]

Answer:

$55.20

Step-by-step explanation:

Create a proportion where x is the cost of 12 lbs of walnuts:

$\frac{3.45}{0.75}$ = $\frac{x}{12}$

Cross multiply and solve for x:

0.75x = 41.4

x = 55.2

So, for 12 lbs of walnuts, it will cost $55.20

8 0

3 years ago

In a study of pain relievers, 50 people were given product A, and all but 11 experienced relief. In the same study, 100 people w

Nataly_w [17]

Answer:

Product B performed worse in the study because 86% failed to get relief with this product, whereas only 78% failed to get relief with Product A

Step-by-step explanation:

We are given the following in the question:

Product A:

Number of people,

$n_1 = 50$

Number of people who received relief,

$x_1 = 11$

Proportion of people who received relief from product A =

$p_A = \dfrac{x_1}{n_1} = \dfrac{11}{50} = 0.22 = 22\%$

Proportion of people who did not received relief from product A =

$1 = p_A = 1 - 0.22 = 0.78 =78\%$

Product B:

Number of people,

$n_2 = 100$

Number of people who received relief,

$x_2 = 14$

Proportion of people who received relief from product B =

$p_B = \dfrac{x_2}{n_2} = \dfrac{14}{100} = 0.14 =14\%$

Proportion of people who did not received relief from product B =

$1 = p_B = 1 - 0.14 = 0.86=86\%$

Product B performed worse in the study because 86% failed to get relief with this product, whereas only 78% failed to get relief with Product A

3 0

3 years ago