Let
rA--------> radius of the circle A
rB-------> radius of the circle B
SA------> the area of the sector for circle A
SB------> the area of the sector for circle B
we have that
rA=5/2 ft
rB=9/2 ft
rA/rB=5/9-----------> rB/rA=9/5
SA=(25/36)π ft²
we know that
if Both circle A and circle B have a central angle , the square
of the ratio of the radius of circle A to the radius of circle B is equals to
the ratio of the area of the sector for circle A to the area of the sector for
circle B
(rA/rB) ^2=SA/SB-----> SB=SA*(rB/rA) ^2----> SB=(9/5) ^2*(25/36)π--->
<span>SB----------- > (81/25)*(25/36)------ > 81/36------
> 9/4π ft²</span>
the answer is
<span>the measure of the sector for circle B is (9/4)π ft²</span>
(x^m)^3=(x^13)^5X(x^-8)^-5 would equal 35.
Answer:
5.05 rupees
Step-by-step explanation:
Convert 5 paisa to rupees
100 paisa = 1 rupees
5/100 = 0.05
5 + 0.05 = 5.05 rupees
1. Angle addition postulate (this could be wrong)
2. Definition of bisect
3. Definition and postulate
4. Screenshot at the bottom
Last one I can't help, my bad.
Note that
- 12=2·2·<u>3</u>;
- 20=2·2·5;
- 36=2·2·<u>3</u>·3.
The common factors of these three numbers are 2, 2. Also numbers 12 and 36 have one more common factor <u>3</u>, then the least common multiple is
LCM(12,20,36)=2·2·<u>3</u>·5·3=180 sec=3 min (here first you write all common factors between all three numbers, then between two numbers and at last all remaining factors).
Answer: all three experiments will need to be checked after 3 minutes passed, then after 6 minutes passed, then after 9 minutes passed and so on.
