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Romashka-Z-Leto [24]
3 years ago
13

What is the product? [1 3 1 -2 1 0] [ 2 -2 3 5 4 1]

Mathematics
1 answer:
nekit [7.7K]3 years ago
8 0

Answer:

   AB = \left[\begin{array}{ccc}15&14\\-1&9\\\end{array}\right]

Step-by-step explanation:

<u><em>Explanation</em></u>:-

Given matrix

      AB  =             \left[\begin{array}{ccc}1&3&1\\-2&1&0\\\end{array}\right]  \left[\begin{array}{ccc}2&-2\\3&5\\4&1\end{array}\right]

multiplication of two matrices

              AB = \left[\begin{array}{ccc}1X 2+3X3+1X4&1X-2+3X5+1X1\\-2X2+1X3+0X4&-2X-2+1X5+0X1\\\end{array}\right]

              AB = \left[\begin{array}{ccc}2+9+4&-2+15+1\\-4+3+0&4+5+0\\\end{array}\right]

           AB = \left[\begin{array}{ccc}15&14\\-1&9\\\end{array}\right]

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Determine the values of x when f(x)=40 for the function f(x)=2(x-3)^2-8
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x = 3 ± \sqrt{24}

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Step-by-step explanation:

given f(x) = 2(x - 3)^2 - 8, find when f(x) = 40

So, we plug in 40 for f(x) in the 1st equation and solve for x.  (Aim to got x on its own)

40 = 2 (x - 3)^2 - 8

+ 8          + 8

-----------------------------

48 = 2 (x - 3)^2

/2            /2

-----------------------------

24 = (x - 3)^2

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--------------------

\sqrt{24} = x - 3

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