5x+3y=58
5x-3y=22
(3y gets cancelled bc 3y-3y=0, then add 5x with 5x, so you're left with)
10x=80, (divide both sides by 10)
x=8
Now we look for y. So choose one formula from the two (let's say 5x + 3y=58)
Substitute x for 8 so it will look like---- 5(8)+3y=58
Multiply 5*8--- so you get -- 40+3y=58
Subtract 40 from both sides and you're left with 3y=18
divide both sides by 3
you get y=6
In conclusion, x=8 and y=6 hence, (8,6)
X-x-2/6=x-7/3+2/3
-2/6+7/3-2/3=x
x= -2/6+5/3
x= 8/6
x= 4/3
Answer:
Step-by-step explanation:
The range is y> 3.
If 19 is half (50%) of something, find that number you would just have to multiply 19 by 2.
This means that 19 is 50% of 38.
Here's an example Its also call the 'ac' method:-
factor 2x^2 - 13x - 15
Multiply first coefficient by last number which is 2*-15 = -30
Now we need 2 factors of -30 which will when added give - 13:-
-15 and 2 looks good. So we can write:-
2x^2 - 13 x - 15
= 2x^2 + 2x - 15x - 15
factor by grouping first 2 and last 2 terms , we get:-
= 2x(x + 1) - 15(x + 1)
the x+1 is common so we have:-
(2x - 15)(x + 1) Answer
Hope this helps.
