Original price = P = $12,698
Depreciation rate = r = 11% = 0.11
Time in years = t = 3
New price = A
The formula used will be:
Using the values, we get:
Thus, the worth of Suzuki after 3 years will be $8951.70
Answer:Just solve it. This is Algebra. Not that hard. Use Substation Method
Step-by-step explanation:
5% is 0.05 in decimals. To get 5% of M, multiply it. To convert a percentage into decimals, divide the number by 100. 20/100 is 0.2. 0.2 is the tip. Do the same as 0.05 and add in the actual cost of the meal (M). Check image
<h3>Answer:</h3><h3>Exact volume =
32pi</h3><h3>Approximate volume =
100.48</h3>
The approximate volume only applies when pi = 3.14
Use either answer, but not both of course.
===============================================
Work Shown:
V = volume of cylinder
V = pi*r^2*h
V = pi*2^2*8
V = pi*32
V = 32pi .... exact volume in terms of pi
V = 32*3.14
V = 100.48 .... approximate volume when we use pi = 3.14
Answer:
a)0.08 , b)0.4 , C) i)0.84 , ii)0.56
Step-by-step explanation:
Given data
P(A) = professor arrives on time
P(A) = 0.8
P(B) = Student aarive on time
P(B) = 0.6
According to the question A & B are Independent
P(A∩B) = P(A) . P(B)
Therefore
& 
is also independent
= 1-0.8 = 0.2
= 1-0.6 = 0.4
part a)
Probability of both student and the professor are late
P(A'∩B') = P(A') . P(B') (only for independent cases)
= 0.2 x 0.4
= 0.08
Part b)
The probability that the student is late given that the professor is on time
= 
= 
= 0.4
Part c)
Assume the events are not independent
Given Data
P
= 0.4
=
= 0.4
= 0.4 x P
= 0.4 x 0.4 = 0.16
= 0.16
i)
The probability that at least one of them is on time
= 1-
= 1 - 0.16 = 0.84
ii)The probability that they are both on time
P
= 1 - 
= 1 - ![[P({A}')+P({B}') - P({A}'\cap {B}')]](https://tex.z-dn.net/?f=%5BP%28%7BA%7D%27%29%2BP%28%7BB%7D%27%29%20-%20P%28%7BA%7D%27%5Ccap%20%7BB%7D%27%29%5D)
= 1 - [0.2+0.4-0.16] = 1-0.44 = 0.56
