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Musya8 [376]
3 years ago
15

11x^2+2-7x-6x^2-12 solve for this equation

Mathematics
2 answers:
andrezito [222]3 years ago
7 0

Answer:

5x^2+2-7x-6x^2-12 ( SEE IMAGE BELOW)

Step-by-step explanation:

FYI you can use the app photo math, you just take a pic of the problem and it gives you the answer and explains the steps and it is free.

Misha Larkins [42]3 years ago
6 0

Answer:

5x^2 - 7x - 10.

Step-by-step explanation:

11x^2+2-7x-6x^2-12

Bring like terms together We get:

11x^2 - 6x^2 - 7x + 2 - 12

= 5x^2 - 7x - 10.

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3 years ago
What is the following quotient? StartFraction RootIndex 3 StartRoot 60 EndRoot Over RootIndex 3 StartRoot 20 EndRoot EndFraction
FrozenT [24]

Answer:

\sqrt[3]{3}

Step-by-step explanation:

We are required to simplify the quotient: \dfrac{\sqrt[3]{60} }{\sqrt[3]{20}}

Since the <u>numerator and denominator both have the same root index</u>, we can therefore say:

\dfrac{\sqrt[3]{60} }{\sqrt[3]{20}} =\sqrt[3]{\dfrac{60} {20}}

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Evaluate the upper and lower sums for f(x) = 2 + sin(x), 0 ≤ x ≤ π, with n = 2, 4, and 8. Illustrate with diagrams like the figu
larisa [96]

f(x)=x+sin(x)\\ a=0\\ b=\pi \\ x_i=a+idelta(x)\\ Upper sum for n=2:\\ \\ delta(x)=\frac{b-a}{n} =\frac{\pi-0}{2} =\frac{\pi}{2}

x_0=0, x_1=\frac{\pi}{2} ,x_1=\pi  \\

Length of the subintervals: [0,\frac{\pi}{2}], [\frac{\pi}{2}, \pi}]

Using Upper Riemann sum,

\int\limits^0_\pi{x+sin(x)\, dx  =∑Max{f(x_i) delta(x)

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Lower sum for n=2:

The minimum value for the function on [0,\frac{\pi}{2}], [\frac{\pi}{2}, \pi] is 2.

\int\limits^0_\pi {x+\sin x} \, dx  =\sum_{n=0}^{n=2} min {f(x_i)} delta (x)\\

= (2+2)\frac{\pi}{2}\\ =6.28

8 0
4 years ago
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