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Mathematics

1 answer:

vodomira [7]3 years ago

5 0

Answer:

Reference angles are always acute.

We can find the reference angle with the "formula"

−

, where

is our given angle.

We can plug

into our expression to get

−

Thus, our reference angle is

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Please help ASAP If f(x) = x^2-6x+2 and g(x) =sqrt x find a.) (fog) (x) b.) (gof) (-2)

Rudik [331]

$\large\begin{array}{l} \left\{\!\begin{array}{l} \mathsf{f(x)=x^2-6x+2}\\ \mathsf{g(x)=\sqrt{x}}\\ \end{array}\right. \end{array}$

$\large\begin{array}{l} \textsf{a) }\mathsf{(f\circ g)(x)}\\\\ =\mathsf{f\big[g(x)\big]}\\\\ =\mathsf{\big[g(x)\big]^2-6\cdot g(x)+2}\\\\ =\mathsf{\big[\sqrt{x}\big]^2-6\sqrt{x}+2}\\\\\\ \therefore~~\boxed{\begin{array}{c}\mathsf{(f\circ g)(x)=x-6\sqrt{x}+2} \end{array}}\qquad\checkmark \end{array}$

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$\large\begin{array}{l} \textsf{b) }\mathsf{(g\circ f)(-2)}\\\\ =\mathsf{g\big[f(-2)\big]}\\\\ =\mathsf{\sqrt{f(-2)}}\\\\ =\mathsf{\sqrt{(-2)^2-6\cdot (-2)+2}}\\\\ =\mathsf{\sqrt{4+12+2}}\\\\ =\mathsf{\sqrt{18}}\\\\ =\mathsf{\sqrt{3^2\cdot 2}}\\\\ =\mathsf{3\sqrt{2}}\\\\\\ \therefore~~\boxed{\begin{array}{c}\mathsf{(g\circ f)(-2)=3\sqrt{2}} \end{array}}\qquad\checkmark \end{array}$

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$\large\textsf{I hope this helps. :-)}$

Tags: composite function composition evaluate algebra

7 0

3 years ago

Two storage sheds are to have the same area. One is square and one is rectangular. The rectangular shed is 4 meters wide and 9 m

aliina [53]

Area is calculated by taking the length times the width.
A=lxw

one shed is 9 x 4 =36 square feet.
the other shed will be the same but have a four sides equal.
a shed with side of 6 x 6 will have a area of 36 square feet.

one side of the square shed would be 6 feet.

brainliest is always appreciated..

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3 years ago

Order the numbers in each list from least to greatest.

Neporo4naja [7]

The answer is letter B

8 0

3 years ago

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Anarel [89]

Answer:

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