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sergejj [24]
3 years ago
9

Which transformation reflects a figure across the y-axis

Mathematics
2 answers:
jeyben [28]3 years ago
6 0
It’s the second one!!!
Inga [223]3 years ago
3 0
It’s the second one .!!!!!!
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See question in attached photo.<br>Answer question 4b and 5c​
sdas [7]

9514 1404 393

Answer:

  4b: 8.6 m/s²; 1.3×10^5 N; 2.1×10^4 N decrease

  5c: -1.6×10^12 J; -1.6×10^12 J

Step-by-step explanation:

<h3>4b</h3>

i) The acceleration due to gravity is inversely proportional to the square of the distance between the objects. The distance to the shuttle is ...

  1 + (5×10^5)/(6.4×10^5) = 69/64 . . . times the radius of the earth

Then the acceleration due to gravity at the height of the space shuttle is about ...

  (10 m/s²)(64/69)² ≈ 8.6 m/s²

__

ii) The weight of the space shuttle at that height is about ...

  F = ma = (15000 kg)(8.6 m/s²) ≈ 1.3×10^5 N

__

iii) The loss of weight will be ...

  ΔF = m(a1 -a0) = (15000 kg)(10 m/s² -8.6 m/s²)

  = 1.5×10^4×1.4 N = 2.1×10^4 N

____

<h3>5c</h3>

i) The gravitational potential energy is given by ...

  U = -GMm/r

where M and m are the mass of the earth and the rocket, respectively.

  U = -(6.67×10^-11)(6.0×10^24)(2.5×10^4)/(6.4×10^6) ≈ -1.6×10^12 J

__

ii) At a height of 3×10^4 m, the denominator in the above expression changes from 6.4×10^6 to 6.43×10^6. This changes the gravitational potential energy by a factor of 6.4/6.43 to -1.6×10^12 J

(Note: we're carrying only 2 significant figures in the result in accordance with the rules for precision in such calculations. The change is noticeable at the level of the 4th significant figure, less than 1/2%.)

4 0
2 years ago
in the 1980s, an average mortgage range was around 18.75%. how much less per month would a $125,000 30 year mortgage be today if
tino4ka555 [31]

Answer:

  $1289.48

Step-by-step explanation:

A financial calculator tells you the payment with the higher interest rate is $1960.51, and that with the lower interest rate is $671.03. The difference in payment amounts is ...

  $1960.51 -671.03 = $1289.48

3 0
3 years ago
Read 2 more answers
A boat has a speed of 15 mph in still water. It travels downstream from Greentown to Glenavon in g hours. It then goes back upst
Lerok [7]

Step-by-step explanation:

We want to find two things-- the speed of the boat in still water and the speed of the current.  Each of these things will be represented by a different variable:

B = speed of the boat in still water  

C = speed of the current

Since we have two variables, we will need to find a system of two equations to solve.

How do we find the two equations we need?  

Rate problems are based on the relationship Distance = (Rate)(Time).


Fill in the chart with your data (chart attached)

The resulting speed of the boat (traveling upstream) is B-C miles per hour.  On the other hand, if the boat is traveling downstream, the current will be pushing the boat faster, and the boat's speed will increase by C miles per hour.  The resulting speed of the boat (traveling downstream) is B+C miles per hour.  Put this info in the second column in the chart.  Now plug it into a formula! <u>Distance=(Rate)(Time) </u>Now solve using the systems of equations!

6 0
3 years ago
Round 10.054 To 2 decimal places
antoniya [11.8K]
The answer to "Round 10.054 To 2 decimal places" is 10.05
3 0
3 years ago
Convert the polar coordinates (-3, -60°) to Cartesian coordinates.
notsponge [240]

Answer:

(1.5,-2.6)

Step-by-step explanation:

Given the polar coordinates (-3,60°).

Let our Cartesian coordinates be (x,y)

#We know that when converting the rectangular coordinates (x,y) to polar (r,θ), then:

r=\sqrt{x^2+y^2}\\\\\therefore r^2=x^2+y^2\\\\\theta=tan^{-1}(y/x)\\\therefore tan \theta=y/x

#Using the illustration above, we can express our polar coordinates as:

-3=\sqrt{x^2+y^2}\\\\-60\textdegree=tan^{-1}(y/x}

#Solve simultaneously to solve for x and y:

(-3)^2=x^2+y^2\ \ \ \ \ \ \ \ \ \ i\\\\tan(-0\texdegree)=y/x\ \ \ \ \ \ \ \ ...ii\\\\y=x\ tan(-60\textdegree)\ \ \ \ \ \ \ ...iii\\\\\#substitute\  y \ in\  i\\\\(-3)^2=x^2+(x \ tan (-60\textdegree))^2\\\\9=x^2+3x^2\\\\x=\sqrt{9/4}=1.5\\\\y=1.5\ tan(-60\textdegree)=-2.5981\approx-2.6

Hence, the Cartesian coordinates are (1.5,-2.6)

6 0
3 years ago
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