<h2>Question 9:</h2>
1. Use Pythagorean Theorem (a²+b²=c²) to solve for missing side of triangle and rectangle. x²+16²=20², or x²+256=400. So, x²=144, and x=12
2. Use formula: 1/2(h)(b1+b2). 1/2 (12) (30+14).
3. Simplify: 1/2 (12) (44)=1/2(528)=264
Area of whole figure is 264 square mm.
<h2>Question 10:</h2>
Literally same thing but with trigonometry.
1. Use sine to find out length of dotted line: sin(60°)=x/12
2: Simplify: 12*sin(60°)=x. x≈10.4 (rounded to the nearest tenth)
3. Use Pythagorean Theorem to find out last leg of triangle: 10.4²+x²=12²
4: Simplify: 108.16 +x²=144. x²=35.84 ≈ 6
5: Use formula: 1/2(h)(b1+b2). 1/2 (10.4) (30+36)
6: Simplify: 1/2 (10.4) (66) =343.2
7: Area of figure is about 343.2
Remember, this is an approximate answer with rounding, so it might not be what your teacher wants. The best thing to do is do it yourself again.
74.4 is the answer.
hope this helps.
18.75÷5=3.75
12.75÷3=4.2
The pack of 5 books has the lower cost per book
Answer:
8 units²
Step-by-step explanation:
The area (A) of the shaded part (right triangle ) is calculated as
A = 
× area of rectangle
= 0,5 × 4 × 4 = 0.5 × 16 = 8 units²
Answer:
See Explanation
Step-by-step explanation:
No trapezoid is attached; so, I will solve on a general note
The area of a trapezoid is:
Using the attached image as a point of reference;
The parallel sides are: AD (6cm) and BD (12cm)
The height is 4cm
So, the area is:
