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Leya [2.2K]
3 years ago
6

What is 2 over seven times five over six?

Mathematics
2 answers:
sukhopar [10]3 years ago
5 0
In its exact form 5/21



Reika [66]3 years ago
3 0

Answer:

the answer is 5/21

Step-by-step explanation:

2/7 × 5/6= 5/21

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Write an exponential function in the form y=ab^x that goes through the point (0,17) and (6,1088)
alexandr402 [8]

Answer:

y = 17(2)^x

Step-by-step explanation:

If the graph of y = ab^x goes through (0, 17), then

                        17 = ab*0, or a = 17

Then the function is y = ab^x with a = 17, or

                                  y = 17*b^x and we must find b.

If the graph of y = 17*b^x also goes through (6, 1088), then the following must be true:   1088 = 17*b^6

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Taking the sixth root of both sides, we get 64^(1/6) = b, and so b = 2

Then the desired exponential function is

y = 17(2)^x

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3 years ago
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What is a cubic polynomial function with zeros 3,3 and -3? show your work.​
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Answer:

Cubic polynomial function with zeros 3,3 and -3 is \mathbf{x^3-3x^2-9x+27=0}

Step-by-step explanation:

We need to find a cubic polynomial function with zeros 3,3 and -3.

If zeros of polynomial are: 3,3,and -3

we can write:

x=3, x=3, x=-3

Or

We can write:

x-3=0, x-3=0, x+3=0

Now, we can write them as:

(x-3)(x-3)(x+3)=0

Multiplying the terms, we can find the polynomial:

(x-3)(x-3)(x+3)=0\\(x(x-3)-3(x-3))(x+3)=0\\(x^2-3x-3x+9)(x+3)=0\\(x^2-6x+9)(x+3)=0\\x(x^2-6x+9)+3(x^2-6x+9)=0\\x^3-6x^2+9x+3x^2-18x+27=0\\x^3-6x^2+3x^2+9x-18x+27=0\\x^3-3x^2-9x+27=0

So, cubic polynomial function with zeros 3,3 and -3 is \mathbf{x^3-3x^2-9x+27=0}

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2 years ago
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