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Leya [2.2K]
3 years ago
6

What is 2 over seven times five over six?

Mathematics
2 answers:
sukhopar [10]3 years ago
5 0
In its exact form 5/21



Reika [66]3 years ago
3 0

Answer:

the answer is 5/21

Step-by-step explanation:

2/7 × 5/6= 5/21

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How many solutions does the system have? <br> y=−2x+1 <br> y=−2x^2+1
balu736 [363]

Answer:

The system has two distinct solutions.

Step-by-step explanation:

The given system of equations are:


y=-2x+1--(1)

and

y=-2x^2+1---(2)


In order to determine the number of solutions the two equations have, we need to equate the two equations to obtain,



-2x^2+1=-2x+1


We now group all terms on the left hand side and equate everything to zero.

-2x^2+2x=0

x^2-x=0


This is now a quadratic equation in x^2 with a=1,b=-1,c=0.

At this stage we check the number of solutions using the discriminant.

D=b^2-4ac


\Rightarrow D=(-1)^2-4(1)(0)=1


Since the discriminant is greater than zero, the equation will have two distinct roots.

Therefore the system of equations has exactly two distinct solutions.


If you wish to see these solutions, you can continue as follows;

We factor x to obtain,

x(x-1)=0


\Rightarrow x=0,x-1=0



\Rightarrow x=0,x=1


When x=0,y=-2(0)+1


Then we have,

x=0,y=1


When x=1,y=-2(1)+1


Then we have,

x=0,y=-1


See graph






8 0
3 years ago
Find an equation of the sphere containing all surface points P = (x, y, z) such that the distance from P to A(−3, 6, 3) is "twic
Marina86 [1]

Answer:

Equation of Sphere =  x^{2} + y^{2} + z^{2} - 18x - 4/3y +10z + 142/3 = 0

Step-by-step explanation:

Data Given:

P = (x,y,z)

Distance from P to A (-3,6,3) = Twice the distance from P to B(6,2,-3)

Solution:

Find the equation of the sphere:

It is given that:

PA = 2PB

Squaring both sides:

(PA)^{2} = (2PB)^{2}

(PA)^{2} = 4 (PB)^{2}

(x - (-3))^{2} + (y - 6)^{2} + (z-3)^{2} = 4 x (x-6)^{2} + (y-2)^{2} + (z-(-3))^{2}

Solving the above equation:

(x + 3))^{2} + (y - 6)^{2} + (z-3)^{2} = 4 x {(x-6)^{2} + (y-2)^{2} + (z + 3))^{2}}

x^{2} + 9 + 6x + y^{2} + 36 - 12y + z^{2} + 9 - 6z = 4 { x^{2} + 36 - 12x + y^{2} + 4 - 4y + z^{2} + 9 + 6z}

x^{2} + 9 + 6x + y^{2} + 36 - 12y + z^{2} + 9 - 6z = 4x^{2} + 144 - 48x +4y^{2} + 16 - 16y + 4z^{2} + 36 + 24z

Putting the right hand side = 0 and solving the equation:

x^{2} - 4x^{2} + y^{2} - 4y^{2} + z^{2} - 4z^{2} + 6x + 48x - 12y +16y -6z - 24z + 9 + 36 + 9 -144 - 16 - 36 = 0

-3x^{2} - 3y^{2}  -3z^{2}  + 54x + 4y -30z -142  = 0

Taking (-) common

- ( 3x^{2} + 3y^{2} + 3z^{2}  - 54x - 4y +30z + 142) = 0

3x^{2} + 3y^{2} + 3z^{2}  - 54x - 4y +30z + 142 = 0

dividing the whole equation by 3

x^{2} + y^{2} + z^{2} - 54/3x - 4/3y +30/3z + 142/3 = 0

x^{2} + y^{2} + z^{2} - 54/3x - 4/3y +30/3z + 142/3 = 0

x^{2} + y^{2} + z^{2} - 18x - 4/3y +10z + 142/3 = 0

7 0
3 years ago
HELP!! PLEASE!! NEED DONE ASAP I WILL GIVE 100 POINTS AND MORE IF YOU CAN GET ALL 3 QUESTIONS DONE!! THANK YOU!! I WILL ALSO MAR
VARVARA [1.3K]

Answer:

I answered the questions but that formatting is very confusing and discourages anyone for trying to answer.

The last question is confusing. If I got it wrong, tell me. I will try to answer in the comment section then.

Step-by-step explanation:

Kayson is looking at two buildings, building A and building B, at an angle of elevation of 73°. Building A is 30 feet away, and building B is 35 feet away. Which building is taller and by approximately how many feet?

$\text{tan}\theta=\frac{h_{A}}{30} \Rightarrow h_{A}=\text{tan}73\º \cdot 30 \Rightarrow h_{A}\approx 98.12 \text{ feet}$

$\text{tan}\theta=\frac{h_{B}}{35} \Rightarrow h_{B}=\text{tan}73\º \cdot 35 \Rightarrow h_{B}\approx 114.47 \text{ feet}$

\text{Difference} \approx 16.35

Building B is around 16.35 feet taller than building A.

A Look at the figure below: an image of a right triangle is shown with an angle labeled y If sin y° = a divided by 6 and tan y° = a divided by b, what is the value of cos y°?

$\text{sin}(y)=\frac{a}{6} $

$\text{tan}(y)=\frac{a}{b} $

a is the opposite side; 6 is the hypotenuse; b is the adjacent side.

Therefore,

$\text{cos}(y)=\frac{b}{6} $

If sin f° = eight ninths and the measure of segment YW is 24 units, what is the measure of segment YX? triangle XYW in which angle W is a right angle, angle X measure f degrees, and angle Y measures d degrees.

This seems a bit confusing. The angles don't match. We have 90\º+62\º +21\º \approx 173\º

\text{sin}(f)=0.888...

f \approx 62\º

YX is the hypotenuse of the right triangle.

$\text{cos}(21\º)=\frac{24}{YX} $

YX \approx 25.7

Considering f \approx 69\º

$\text{sin}(69\º)\approx\frac{24}{YX} $

YX \approx 25.7

4 0
3 years ago
Read 2 more answers
If the acceleration of an object is given by dv/dt = −2v, Find the position function s(t) if v(0) = 7 and s(0) = 0.
kirill [66]

Answer:

Step-by-step explanation:

Given that acceleration of an object is

\frac{dv}{dt} =-2v\\\frac{dv}{v} =-2dt\\ln v = -2t+C\\

is the solution to the differential equation

Since v(0) =7

we get ln 7 = C

Hence lnv = -2t+ln 7\\v=7e^{-2t}

since velocity is rate of change of distance s we have

v=\frac{ds}{dt} =7e^{-2t}\\s= [tex]s(t) =\frac{-7}{2} (e^{-2t})+C)[

substitute t=0 and s=0

C=7/2

So solution for distance is

s(t) =\frac{-7}{2} (e^{-2t}-1)

4 0
3 years ago
How many unique triangles can be made with 3,5,8
blondinia [14]

Answer

2 or 3

Step-by-step explanation:

3 0
3 years ago
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