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3 years ago

Find the points of Intersection of these graphs

Mathematics

1 answer:

geniusboy [140]3 years ago

8 0

Answer:

the line crosses the parabola at (-2,4) and (3,9)

Step-by-step explanation:

y=x^2

y=x+6

set them equal to each other

x^2=x+6, now set it equal to zero

x^2-x-6=0, now find the root

(x+2)(x-3)=0, the x=-2, and x=3; now substitute into any of the equation to find the points where graphs intercept

at x= -2, y=(-2)^2=4, so one point is (-2,4)

at x=3, y=(3)^2=9, so other point is (3,9)

the line crosses the parabola at (-2,4) and (3,9)

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The length of an object is measured as 65.8 centimeters what is this measurement in scentific notation

julsineya [31]

Answer:

6.58 x 10^1

Step-by-step explanation:

This is because the exponent 1 means that you have to move the decimal place in 6.58 to the right once which makes the standard form 65.8. And vice versa, if you move the decimal place to the left once in 65.8, then the answer is 6.58 x 10^1.

7 0

2 years ago

Danielle makes the claim that when the polynomial x^2-3x-10 is divided by x-5, the remainder is 0. Use what you have learned abo

Mumz [18]

Answer:

<h3>Daniel is correct</h3>

Step-by-step explanation:

Given the polynomial P(x) = x^2-3x-10

To check that the remainder is zero if divided by x - 5, we will first have to equate x - 5 to zero and get x;

x - 5 = 0

x = 5

Then find P(5)

P(5) = 5^2 - 3(5) - 10

P(5) = 25 - 15 - 10

P(5) = 25-25

P(5) = 0

<em>This shows that x - 5 is a factor of the polynomial since P(5) gave us zero according to the factor theorem</em>

7 0

3 years ago

Smallest 7 digit even number

Marrrta [24]

1,000,000, because its the 1st 7 digit number and it happens to be even

3 0

3 years ago

you are rolling a 10-sided die with sides numbered 1-10. you keep rolling the die until you roll a prime number and then stop. l

evablogger [386]

The formula for E(x) would be SUM[ X(n)P(n)] from n = 1 to n = infinity until we get the prime number

In the given problem, a 10-sided die with 1-10 numbers is rolled until we get a prime number

Prime numbers between 1-10 = 2,3,5,7 (4 prime numbers)

Non - prime numbers = 1,4,6,8,9,10( 6 non-prime number)

Let X be the number of times the die is rolled

The probability of getting a prime =

$P(Prime) = \frac{4}{10}$

Now, the value of

E(X)=∑x.P(x) [ x-> {1, infinity}]

= P(1)X(1) +P(2)X(2)+P(3)X(3)+P(4)X(4)........+ P(n)X(n)

= 1. $\frac{4}{10}$ + 2. $\frac{6}{10}$ . $\frac{4}{10}$ + 3. $\frac{6}{10}$ . $\frac{6}{10}$ $\frac{4}{10}$ + 4. $\frac{6}{10}$ . $\frac{6}{10}$ . $\frac{6}{10}$ . $\frac{4}{10}$ .......

Hence, this is the value of E(x)

To learn more about Prime number, here

brainly.com/question/9315685

#SPJ4

4 0

2 years ago

How do I solve this

sdas [7]

$\bf \textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
-------------------------------\\\\
\cfrac{2x}{x^2+2x-24}-\cfrac{x}{x^2-36}\quad 
\begin{cases}
x^2+2x-24\implies (x+6)(x-4)\\
--------------\\
x^2-36\implies x^2-6^2\\
(x-6)(x+6)
\end{cases}$

$\bf \cfrac{2x}{(x+6)(x-4)}-\cfrac{x}{(x-6)(x+6)}\impliedby 
\begin{array}{llll}
\textit{thus our LCD is}\\
(x-6)(x+6)(x-4)
\end{array}
\\\\\\
\cfrac{[(x-6)2x]~-~[(x-4)x]}{(x-6)(x+6)(x-4)}\implies \cfrac{2x^2-12x-x^2+4x}{(x-6)(x+6)(x-4)}
\\\\\\
\cfrac{x^2-8x}{(x-6)(x+6)(x-4)}$

3 0

3 years ago