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Kryger [21]
3 years ago
15

I need help plz !!!!!!!!! ​

Mathematics
1 answer:
katen-ka-za [31]3 years ago
4 0

Answer:

it x=-2(y-7)

            3

Step-by-step explanation:

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Paula, the local baker, usually makes 1"5 loaves of bread and 10 cakes per day, but today she made 25 loaves of bread and 12 cak
frozen [14]

Answer:

the percentage increase for bread and cake is 66.67% and 20% respectively  

Step-by-step explanation:

The computation of the percentage increase for each bakery item is shown below:

For bread

= (25  - 15) ÷ 15

= 66.67%

For cakes

= (12 - 10) ÷ (10)

= 20%

Hence, the percentage increase for bread and cake is 66.67% and 20% respectively  

3 0
2 years ago
The mean annual income for people in a certain city is 37 thousand dollars, with a standard deviation of 28 thousand dollars. A
Aloiza [94]

Answer:

P( 31 < \bar X< 41)

And we can ue the z score formula given by:

z= \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And using this formula we got for the limits:

z = \frac{31-37}{\frac{28}{\sqrt{50}}}= -1.515

z = \frac{41-37}{\frac{28}{\sqrt{50}}}= 1.01

So we want to find this probability:

P(-1.515

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the annual income of a population, and for this case we know the following info:

\mu=37 and \sigma=28  and we are omitting the zeros from the thousand to simplify calculations

We select a sample size of n=50>30.

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we want to find this probability:

P( 31 < \bar X< 41)

And we can ue the z score formula given by:

z= \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And using this formula we got for the limits:

z = \frac{31-37}{\frac{28}{\sqrt{50}}}= -1.515

z = \frac{41-37}{\frac{28}{\sqrt{50}}}= 1.01

So we want to find this probability:

P(-1.515

4 0
3 years ago
The purchasing director of a bank has just received a shipment of 100 printers. She has been told that the shipment includes 5 d
zaharov [31]
Since there is a 95% chance that you get two printers right, then you simply square the decimal equivalent which is .95 (Hence, you do .95^2). You will get .9025 (or 90.25%). 

For letter b, you simply subtract .9025 from 1. 
ans = 1-.9025
ans = .0975 (or 9.75%)

So the answer to B) would be there is a 9.75% chance the probability of a shipment can be rejected.
8 0
3 years ago
Jack picked 56 apples. He will give each friend 3 apples.
sergey [27]
18 friends will get apples i think
3 0
3 years ago
Read 2 more answers
Choose the linear equations.
andrew-mc [135]

Answer:

y = \frac{3}{3}x - 5

y = 2x + 5

Step-by-step explanation:

In linear equations, both variables x and y must have the exponent of 1 (i.e. they cannot have a small number at the top-right). And they cannot be in the exponents (i.e. cannot be the small number at the top-right).

7 0
3 years ago
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