Answer:
a.2s b.43.6m
Step-by-step explanation:
h(t)=−4.9t2+19.6t+24
24m = inittial possition
-4.9 t2= -1/2 g t2
19.6t= Vo t
as the initial velocity is positive, the ball is thrown up.
the maximum height of the ball is reached when the velocity is 0
V= Vo-gt=19.6m/s-9.8m/s2 t=0
t=19.6/9.8=2s
<u>it takes 2seconds for the ball to reach its maximum height</u>
h(t)=−4.9t2+19.6t+24
h(2)=-19.6m+39.2m+24=43.6m
<u>the maximum height of the ball is 43.6m</u>
Answer:
#3
Step-by-step explanation:
The line follows an inverted slope format, indicated by -2/3. Or down 2, and 3 to the right after going up by 4, creating the line. The other equations would flip the line horizontally because of a positive slope.
Instead i use pemdas so the answer to this problem would be 48