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maw [93]
3 years ago
12

The midpoint of AB is M(6, 3) . If the coordinates of A are (7, 4) , what are the coordinates of B?

Mathematics
1 answer:
timofeeve [1]3 years ago
8 0

Answer:

5,2

Step-by-step explanation:

the difference between a and m is 1,1 so 1,1 subtracted from the mid point(M) would be 5,2

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In football a field goal is worth 3 points which function rule relates the number of field goals f and the number of points p
Strike441 [17]
The answer would be B. If you want to FIND how many points a person has, you put the "p" on its own on the left of the equation, and since every field goal (f) you score is worth 3 points, just multiply "f" by 3 (3f).

For example, if someone scored 5 field goals in a game, to find how many points they totalled, just plug in the 5 for "f":

1. Get equation:

p = 3f

2. Plug in field goals for "f":

p = 3(5)

3. Solve:

p = 15
4 0
3 years ago
Compare using >,=, or >.
il63 [147K]

Answer:

5 = 5

5 < 6

7 > 6

Step-by-step explanation:

The two slashes is the equal sign, comparing two numbers that are of the same value. The sign below that means "less than," and 5 is less than 6. The sign below the "less than" sign is the "greater than" sign, and in the given example, 7 is GREATER THAN 6.

4 0
3 years ago
PLEASE HELP: Find the measure of the angle indicated. Arc BC is 80 degrees.
Marina CMI [18]
The angle is 80 degrees. The measure of an angle is the exact same as the angle measure of the included arc, so that makes angle BAC 80 degrees
7 0
3 years ago
PLEASE HELP!!! MATH IS HORRIBLE! URGENT!!
torisob [31]

Answer:

A. m-6/24

Step-by-step explanation:

This is the required expression because,

1. Quotient of 24 and 6 less than m.

2. It means quotient of 24 and 6 subtracted from m.

3. Representing it mathematically, m-6/24.

5 0
3 years ago
Read 2 more answers
At which values of x does the function F(x) have a vertical asymptote? Check all that apply. F(x)=2/3x(x-1)(x 5).
Alekssandra [29.7K]

The function F(x) have a vertical asymptote at x =0 and x =1.

Given that

The given Function;

\rm  F(x)=\dfrac{2}{3x(x-1)(x^ 5)}

We have to determine

At which value the function F(x) has a vertical asymptote.

According to the question

The given Function;

\rm  F(x)=\dfrac{2}{3x(x-1)(x^ 5)}

The function is undefined when the denominator becomes 0. Find values of x for which the denominator is 0:

Then,

\rm 3x (x-1) (x^5)= 0

\rm x^5 =0, \ \  x=0\\\\ x-1 = 0, \ \ x =1\\

The value of x is 0 and 1.

Hence, the function F(x) have a vertical asymptote at x =0 and x =1.

To know more about Parabola click the link given below.

brainly.com/question/12868913

7 0
2 years ago
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