1) No, because the line does not divide the figure into two mirrored images.
2)Yes, because the line divides the figure into two mirrored images.
3) Yes, because the line divides the figure into two mirrored images.
4)No, because the line does not divide the figure into two mirrored images.
5)One line, vertical down the middle.
6) Zero lines, because the figure can not be divided into mirrored images.
7)Four lines, horizontal down the middle, vertical down the middle and diagonal down from each top corner.
8) One line, vertical down the middle
Answer: stop pay attention in class
Step-by-step explanation:
![\text{Let the product of two natural numbers p and q is 590, and their HCF is 59}\\ \\ \text{we know that the product of LCM and HCF of any two numbers is equal}\\ \text{to the product of the numbers. that is}\\ \\ \text{HCF}\times \text{ LCM}=p\times q\\ \\ \Rightarrow 59 \times \text{LCM}=590\\ \\ \Rightarrow \text{LCM}=\frac{590}{59}\\ \\ \Rightarrow \text{LCM}=10\\ \\ \text{for any two natural numbers, their Least Common Multiple (LCM) is always}](https://tex.z-dn.net/?f=%20%5Ctext%7BLet%20the%20product%20of%20two%20natural%20numbers%20p%20and%20q%20is%20590%2C%20and%20their%20HCF%20is%2059%7D%5C%5C%0A%5C%5C%0A%5Ctext%7Bwe%20know%20that%20the%20product%20of%20LCM%20and%20HCF%20of%20any%20two%20numbers%20is%20equal%7D%5C%5C%0A%5Ctext%7Bto%20the%20product%20of%20the%20numbers.%20that%20is%7D%5C%5C%0A%5C%5C%0A%5Ctext%7BHCF%7D%5Ctimes%20%5Ctext%7B%20LCM%7D%3Dp%5Ctimes%20q%5C%5C%0A%5C%5C%0A%5CRightarrow%2059%20%5Ctimes%20%5Ctext%7BLCM%7D%3D590%5C%5C%0A%5C%5C%0A%5CRightarrow%20%5Ctext%7BLCM%7D%3D%5Cfrac%7B590%7D%7B59%7D%5C%5C%0A%5C%5C%0A%5CRightarrow%20%5Ctext%7BLCM%7D%3D10%5C%5C%0A%5C%5C%0A%5Ctext%7Bfor%20any%20two%20natural%20numbers%2C%20their%20Least%20Common%20Multiple%20%28LCM%29%20is%20always%7D%20)
![\text{greater than their HCF.}\\ \\ \text{but here we can see that }LCM](https://tex.z-dn.net/?f=%20%5Ctext%7Bgreater%20than%20their%20HCF.%7D%5C%5C%0A%5C%5C%0A%5Ctext%7Bbut%20here%20we%20can%20see%20that%20%7DLCM%20%3CHCF%20)
Hence there is no such natural numbers exist.
This question was posted almost a week ago, and I am not sure if you still need the answer, but I'll explain it.
The total number of all of the shapes were placed in the bag are equal to 100. The number comes from adding 32+20+48=100.
This is our total number and will be the denominator.
There are a total of 32 cards which have a hexagon, this number will be our numerator.
So far we have 32/100 , but this is not simplest form.
Next to reduce the fraction, the GCF must be found.
32: 1, 2, 4, 8, 32
100: :
Answer:(0)-12,-15
Step-by-step explanation: