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MrMuchimi
3 years ago
5

QUICK HELP PLEASE! THANK YOU SO MUCH

Mathematics
1 answer:
Oliga [24]3 years ago
6 0

Answer:

 T

              fold it up =t

Step-by-step explanation:

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PLEASE HELP VERY IMPORTANT
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Answer:

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Given: E is the midpoint of DF<br> Prove: 2DE = DF
Lostsunrise [7]
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4 years ago
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class size m average 0.82 n class n average 0.78. if the average for combined classes is 80%, what is relationship between m and
katen-ka-za [31]

Answer:

The relation between m and n is ,  m = n      

Step-by-step explanation:

Given as :

The average for n class  = 0.82 = 82%

The average for m class  = 0.78 = 78%

The average for ( m + n ) class  = 80%

So , \frac{x_1 +x_2+x_3+x_4+ ....... + x_n}{n} = 82%

And \frac{x_1 +x_2+x_3+x_4+ ....... + x_m}{m} = 78%

And , \frac{(x_1+x_2+x_3+x_4+ ......+x_n ) + (x_1+x_2+x_+x_4+.....+x_m)}{m+n} = 80%

So , 0.82×n + 0.78×m = 0.80× (m+n)

Or,  0.82×n - 0.80×n = 0.80×m -   0.78×m

Or,   0.02×n              =  0.02×m

Or,   \frac{m}{n} =  \frac{0.02}{0.02}

∴      \frac{m}{n} = 1

I.e     m  =  n

Hence The relation between m and n is ,  m = n      Answer

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3 years ago
How do I Solve this problem?
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4 years ago
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