Answer:
2/11
Step-by-step explanation:
6/33 simplified to lowest terms is 2/11.
Answer:im not sure i wish i can help but goodluck
Step-by-step explanation:
Solve the system if equations by subtracting:
We get 5L = 45
L = 9
Substituting for L in s = 20L + 75 gives s = 255
So the second choice I the correct one
Answer:
![P(9.6 < \bar X](https://tex.z-dn.net/?f=%20P%289.6%20%3C%20%5Cbar%20X%20%3C15.6%29%20%3DP%28-0.8%3Cz%3C1.2%29%3D%20P%28Z%3C1.2%29-%20P%28Z%3C-0.8%29)
And using the normal standard distribution or excel we got:
![P(9.6 < \bar X](https://tex.z-dn.net/?f=%20P%289.6%20%3C%20%5Cbar%20X%20%3C15.6%29%20%3DP%28-0.8%3Cz%3C1.2%29%3D%20P%28Z%3C1.2%29-%20P%28Z%3C-0.8%29%3D0.8849-%200.2119%3D0.6731%20)
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Solution to the problem
Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:
Where
and
Since the dsitribution for x is normal then we know that the distribution for the sample mean
is given by:
We want to find this probability:
![P(9.6 < \bar X](https://tex.z-dn.net/?f=%20P%289.6%20%3C%20%5Cbar%20X%20%3C15.6%29)
And we can use the z score formula given by;
![z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}](https://tex.z-dn.net/?f=%20z%20%3D%20%5Cfrac%7B%5Cbar%20X%20-%5Cmu%7D%7B%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%7D)
And if we find the z score for the limits given we got:
![z = \frac{9.6-12}{\frac{6}{\sqrt{4}}}= -0.8](https://tex.z-dn.net/?f=%20z%20%3D%20%5Cfrac%7B9.6-12%7D%7B%5Cfrac%7B6%7D%7B%5Csqrt%7B4%7D%7D%7D%3D%20-0.8)
![z = \frac{15.6-12}{\frac{6}{\sqrt{4}}}= 1.2](https://tex.z-dn.net/?f=%20z%20%3D%20%5Cfrac%7B15.6-12%7D%7B%5Cfrac%7B6%7D%7B%5Csqrt%7B4%7D%7D%7D%3D%201.2)
So we can calculate this probability like this:
![P(9.6 < \bar X](https://tex.z-dn.net/?f=%20P%289.6%20%3C%20%5Cbar%20X%20%3C15.6%29%20%3DP%28-0.8%3Cz%3C1.2%29%3D%20P%28Z%3C1.2%29-%20P%28Z%3C-0.8%29)
And using the normal standard distribution or excel we got:
![P(9.6 < \bar X](https://tex.z-dn.net/?f=%20P%289.6%20%3C%20%5Cbar%20X%20%3C15.6%29%20%3DP%28-0.8%3Cz%3C1.2%29%3D%20P%28Z%3C1.2%29-%20P%28Z%3C-0.8%29%3D0.8849-%200.2119%3D0.6731%20)
The slope is -9
Y intercept is -6