Find the critical points of 
:
All three points lie within 
, and 
takes on values of
Now check for extrema on the boundary of . Convert to polar coordinates:
Find the critical points of 
:
where 
is any integer. There are some redundant critical points, so we'll just consider 
, which gives
which gives values of
So altogether, has an absolute maximum of 65/16 at the points (0, -1/2) and (0, 1/2), and an absolute minimum of 3 at (-1, 0).
<span>So the question is what are three equivalent ratios for 4/3, 12/14 and 6/9. The simplest way to get the equivalent ratio of some other ratio is to either multiply the nominator and the denominator by the same number or to divide the nominator and the denominator with the same number. I need to point out that it's not always possible to divide them and get a whole number. First: (4/3)*(2/2)=8/6, (4/3)*(3/3)=12/9 and (4/3)*(4/4)=16/12. Second: (12/14)/(2/2)=6/7, (12/14)*(2/2)=24/28 and (12/14)*(3/3)=36/42. Third: (6/9)/(3/3)=2/3, (6/9)*(2/2)=12/18 and finally (6/9)*(3/3)=18/27.</span>
Area of a Triangle= 1/2 (bh)
96=1/2(b x 8)
96/8=1/2b
12=1/2b
12 x 2/1=b
24=b
A=1/2(24(8))
P=24 x 3
P=72
