5/6x -4 = -2
5/6x = 2
multiply both sides by 6 to get rid of the fraction.
5x = 12
x = 2.4
Answer:
A
Step-by-step explanation:
The velocity of a moving body is given by the equation:

Is the velocity is <em>positive </em>(v>0), then our object will be moving <em>forwards</em>.
And if the velocity is negative (v<0), then our object will be moving <em>backwards</em>.
We want to find between which interval(s) is the object moving backwards. Hence, the second condition. Therefore:

By substitution:

Solve. To do so, we can first solve for <em>t</em> and then test values. By factoring:

Zero Product Property:

Now, by testing values for t<1, 1<t<4, and t>4, we see that:

So, the (only) interval for which <em>v</em> is <0 is the second interval: 1<t<4.
Hence, our answer is A.
Answer:
x = 16
y = -24
Step-by-step explanation:
Recall that the addition of matrices is done when matrices are of the same dimension. In this case, you are in fact adding matrices of the same dimension (dimension 1x2). Recall as well that in the addition of matrices, the elements of each matrix combine only with the element located in the exact same position in the other matrix.
So for this case the first element of the first matrix "16" combines with the first element of the second matrix "0" resulting in an element of value16 + 0 =16 in the new matrix.
Equally, the second element of the first matrix "-24" combines with the second element of the second matrix, resulting in : -24 + 0 = -24.
Therefore, the matrix resultant from this addition is: [16 -24] (same form of the first matrix, which indicates that adding a zero matrix to an existing matrix will not change the first matrix.