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ratelena [41]
3 years ago
14

I really need help plssss

Mathematics
1 answer:
ZanzabumX [31]3 years ago
4 0

1jahsjsjsbskshjeiebeiejiejeiejwjebbs

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The height of a hot air ballon is tracked as it makes trip from launch to the landing site. Look at the graph to determine what
Novosadov [1.4K]

Answer:

c

Step-by-step explanation:

The graph is gradually decreasing but stops

7 0
3 years ago
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Ashley adds Polynomial A and B together:
icang [17]

Answer:

coefficient of x: 2

coefficient of y: 3

coefficient of z: -7

Step-by-step explanation:

To solve this problem, first we need to sum the polynomials A and B, then we need to check the coefficients of x, y and z.

The sum of the polynomials is:

A + B = 5z + 4x^2 - 6y + 2 + 2x + 9y - 12z - 2

A + B = 4x^2 + 2x + 3y - 7z

So, the coefficients are:

coefficient of x^2: 4

coefficient of x: 2

coefficient of y: 3

coefficient of z: -7

3 0
4 years ago
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I need it ASAP please help!!
alekssr [168]

Answer:

5,4,6,-7

Step-by-step explanation:

The y's are range

4 0
3 years ago
Please help!! I’m not sure how to answer this question!!
nlexa [21]
<h3>Answer:  9V</h3>

=============================================================

Reason:

The volume expression of a cone with radius r and height h is

\frac{1}{3}\pi*r^2*h

Let's plug in the given height h = 12 and we'd get

\frac{1}{3}\pi*r^2*h\\\\\frac{1}{3}\pi*r^2*12\\\\\left(\frac{1}{3}*12\right)\pi*r^2\\\\4\pi*r^2\\\\

This is the volume of the first cone. We're told the first cone has a volume of V, so we can say V = 4\pi r^2

We can't find the actual numeric volume because we don't know what value replaces r. So we leave it as is.

The second cone has the same height (h = 12) but the radius is now 3 times in size. Instead of r, we use 3r

Replace every copy of r with 3r. Then simplify

4\pi*r^2\\\\4\pi*(3r)^2\\\\4\pi*9r^2\\\\9(4\pi r^2)\\\\9V\\\\

The radius tripled which results in a volume that's 9 times bigger.

3 0
2 years ago
(3x3 + 2x2 − 5x) − (8x3 − 2x2).
uranmaximum [27]
My answer -

-5x^3+4x^2-5x

P.S

Have an AWESOME!!! LBGT Day :)


3 0
4 years ago
Read 2 more answers
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