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vladimir1956 [14]
3 years ago
12

Please help with this qaestion

Mathematics
2 answers:
Luden [163]3 years ago
5 0
The answer is 66
Hope this helped !!
aivan3 [116]3 years ago
5 0
15+(25+26)*1
Order of operations, parenthesis first
15+51*1
Next multiplication
15+51=66

Hope that helps


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What is -18 + (-45) + 12
qaws [65]
The answer is -51, hope this helps
5 0
3 years ago
Read 2 more answers
Given the sequence 12, 9, 6, 3,........ where x = 0, 1, 2......,
Nitella [24]

Answer:

f(x) = -3x + 12

Step-by-step explanation:

The chart could be represented like this:

x             y

0            12

1             9

2            6

3            3

Suppose that f(x) = y

And substitute x values.

y = -3x + 12

"x = 0"

y = -3(0) + 12

y = 0 + 12

y = 12

"x = 3"

y = -3(3) + 12

y = -9 + 12

y = 3

From the results, it corresponds to the function.

4 0
3 years ago
PLEASE HELP!!! I WILL GIVE BRAINLIEST!! 98 POINTS!! Fake answers will get reported. ONLY QUESTIONS
Brums [2.3K]
1.Y=20
2. THE NUMBER GETS BIGGER
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5 0
3 years ago
Read 2 more answers
Factor 6(×)^3+43(×)^2+79(×)+12
Marysya12 [62]
The answer is (6x+1)•(x+4)•(x+3)
3 0
3 years ago
Elimination method: ax+by=r, -bx+cy=s
Alex17521 [72]
\left[\begin{array}{ccc}ax+by=r\\\\-bx+cy=s\end{array}\right]

Isolate x for ax+by=r

x= \frac{r-by}{a} ; a \neq 0

Subsititute x= \frac{r-by}{a}

-b \frac{r-by}{a} +cy=s

Isolate r for : -b \frac{r-by}{a}+cy=s

r=- \frac{as-acy-b^2y}{b} ; a \neq 0;b \neq 0

For x : \frac{r-by}{a}

Subsititute r = - \frac{as-acy-b^2y}{b}

x= -\frac{as-acy-b^2y}{b}/a

x =  \frac{cy-s}{b}

The solutions to the system of equations are:

r= -\frac{as-acy-b^2y}{b} and <span> x = \frac{cy-s}{b}
</span>
hope this helps!


3 0
2 years ago
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