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Anon25 [30]
3 years ago
13

Please help and quick thanks

Mathematics
2 answers:
Travka [436]3 years ago
6 0

Answer:

C. 2x^2 - 14x +7

Step-by-step explanation:

mamaluj [8]3 years ago
5 0

Here is a picture of the answer.

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A sequence can be generated by using an = an-1 + 4, where a1 = 6 and n is a whole number greater than 1. What are the first four
Firlakuza [10]

<u>Answer:</u>

  • The first four terms are <u>4</u><u>,</u><u>8</u><u>,</u><u>1</u><u>2</u><u>,</u><u>1</u><u>6</u>

<u>Step-by-Step </u><u>Explanation</u><u>:</u>

The given relation between the nth term and it's previous term is given by:

\boxed{an = an - 1 + 4}

GiveN:

  • a1 = 4

Now finding the other three terms of the AP with the given relation.

a2 = a1 + 4

Putting a1 = 4,

a2 =  4 + 4 = 8

Now, Third term:

a3 = a2 + 4

Putting a2 = 8,

a3 = 8 + 4 = 12

Now, Fourth term:

a4 = a3 + 4

Putting a3 = 12,

a4 = 12 + 4 = 16

Hence, The first four terms of the AP is 4, 8, 12 & 16.

7 0
3 years ago
You were given the polynomial f(x)=3x^3+13x^2+19x+k and you know that f(-2)=0find k
eduard

Answer:

k = 10

Explanation:

The initial polynomial is:

f(x)=3x^3+13x^2+19x+k

If f(-2) = 0, then when we replace x by -2, the result will be 0. It means that we can write the following equation:

\begin{gathered} f(-2)=3(-2)^3+13(-2)^2+19(-2)+k=0 \\ 3(-2)^3+13(-2)^2+19(-2)+k=0 \end{gathered}

Therefore, we can solve for k as follows:

\begin{gathered} 3(-8)+13(4)+19(-2)+k=0 \\ -24+52-38+k=0 \\ -10+k=0 \\ -10+k+10=0+10 \\ k=10 \end{gathered}

So, the value of k is 10

6 0
1 year ago
Hi can i calculate difficult maths question
Juli2301 [7.4K]

Answer:

I think you could if you tried.


4 0
3 years ago
2<br>54% of 125 is what?<br>3. What percent of 200 is 104?<br>4. What percent of 124 is 62?​
Dovator [93]

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My nickname - Lovely

7 0
3 years ago
Question 7
umka21 [38]

Answer:

A. √16

Step-by-step explanation:

A perfect square is any number that can be expressed as a product of an integer and itself. i.e. 4 can be represented as 2 × 2. Therefore, 4 is a perfect square.

From the options given, the only radical expression that has two perfect square is √16.

√16 consists of two perfect squares, which are 4 and 4.

4 can be expressed as 2 × 2.

Thus: √16 = √(2 × 2)(2 × 2).

Therefore, √16 consists of two perfect squares.

5 0
3 years ago
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