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ivanzaharov [21]
3 years ago
8

Write an equation for the parabola that satisfies

Mathematics
1 answer:
givi [52]3 years ago
4 0

Answer:

Step-by-step explanation:

y = -3(x-3)^2 + 4

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What is -3 (5a + 2 + 3c) simplified?​
GuDViN [60]
-15a - 9c -6 should be right :)
6 0
3 years ago
Find the unknown digit to make each statement true <br> 3.59 &gt; 3.5 1 &gt;3.572
Softa [21]

We are given statement 3.59 > 3.5__1 >3.572.

We have a blank space in between 5 and 1 in the middle number given.

Given statement ccan be read as :

3.59 is greater than 3.5__1 is greater than 3.572.

So, we need to check a number that is less than 3.59 but less than 3.572.

The hundredth place of 3.59 number is 9 and

hundredth place of 3.572 number is 7.

So, we need to find a number between 7 and 9.

8 is the number in between 7 and 9.

So, the known digit can be replaced by 8 to make the statement true.

And final statement is 3.59 > 3.581 >3.572.

6 0
3 years ago
Read 2 more answers
A bicycle tire has a diameter of 3 feet. How many turns of the wheel could it take for the bicycle to go 792 feet?​
Andrew [12]

Answer:

84 complete turns

Step-by-step explanation:

In order to find the number of turns that the bicycle wheel is going to take while going 792 feet, we need to find the circumference of the wheel.

C = \pi \: d = 3.14 \times 3 = 9.42 \: ft \\ no \: of \: turns =  \frac{792}{9.42}  \\  = 84.0764331 \\  = 84 \: turns

7 0
3 years ago
4(x + 10) &lt; 20 What is the answer
lukranit [14]

Answer:

x < -5

Step-by-step explanation:

Distribute 4 to x and 10: 4x + 40 < 20

Subtract 40 from both sides: 4x < -20

Divide by 4: x < -5

6 0
2 years ago
The average length of a ladybug can range from 0.08 to 0.4 inches. Find two lengths that are within the given span.Write them as
Alenkinab [10]
The average length of a ladybug can range from 0.08 to 0.4 inches.

So two lengths within the given span are 0.1 inch and 0.3 inches.

In  \: fraction: \\  \\ 0.1 \: inch =  \frac{1}{10}  \: inch \\  \\ 0.3 \: inch =  \frac{3}{10}  \: inch
7 0
3 years ago
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