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telo118 [61]
3 years ago
12

What is the base two representation of the number 129?

Mathematics
1 answer:
makkiz [27]3 years ago
4 0

Answer:

I think its C

You might be interested in
Which represents the inverse of the function f(x) = 4x
Mademuasel [1]

Answer:

f(x) = x/4

Step-by-step explanation:

To find the inverse of a function replace the positions of x and y. Then isolate y.

y = 4x

x = 4y

x/4 = y

f(x) = x/4

5 0
3 years ago
Solve y + (-18) = -12
natali 33 [55]

Answer:

Y = 6 I’m pretty sure if its not 6 it’s -6

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
I need help w this pls :)
Llana [10]

Answer:

x8 y6

Step-by-step explanation:

5 0
3 years ago
(x+3)^2 + 16/(x+3)^2 = 92 <br><br> x + 1/(x+3) = ??
Irina-Kira [14]
One
Remark

This is very complicate unless you pick the right method. It's very handy o know about substitutions.

Method
Let z = (k + 2)^2

Now the problem becomes
z + 16/z = 92           Multiply through by z 

Solution
z^2 + 16 = 92z
That does not look very promising. If you know the quadratic formula, this mess can be solved. If you do not know what the quadratic formula is, then what I've written is the answer. 

Worse yet, you have to know what complex numbers are. Is this something you know about? The z form of this equation is fine. It gives answers that are rational. The problem is that both are negative and so in your next step, you will be forced to take the square root of a negative number.

Maybe the answer is just
(x + 3)^ + 16 = 92(x + 3)^2
If all you have to do is expand this then you get
x^2 + 6x + 9  + 16 = 92(x^2 + 6x + 9) Remove the brackets.
x^2 + 6x + 25 = 92x^2 + 552x + 828  Put the left over to the right.
0 = 92x^2 - x^2 + 552x - 6x + 828 - 25
0 = 91x^1 + 546x + 803


It looks that way from the second question. If I'm wrong about that, put a comment down below.

Two
 Put over a common denominator and expand
\frac{(x + 3)^2 + 1}{(x + 3)^2}  =  \frac{x^2 + 6x + 9 + 1}{x^2 + 6x + 9} =  \frac{x^2 + 6x + 10}{x^2 + 6x + 9}
3 0
3 years ago
Please help me! I'm spending 50 points on this question and my last two questions never even got answered!
Verdich [7]

Answer:

C.

Step-by-step explanation:

Domain is only affected if certain values can make the result something that either doesn't make sense or is an error. In your situation, it wants you to find the domain of f/g, which is a fraction. The only rule we have for fractions regarding domain is that we simply can't divide by zero, to find the domain for any fraction with variables in the denominator, what I do is take the denominator, set it equal to 0, and solve for x.

So, if we're taking f/g, we have:

\frac{3x^2 + x^4 + 2}{4x - 3}

4x - 3 makes up our denominator, the bottom part of the fraction. So

4x - 3 = 0

4x = 3

x = 3/4

So the denominator is equal to zero when x is equal to 3/4. This would produce an error in any calculator because you can't divide by zero. The domain here is all real numbers except for 3/4.

(For future problems, the only thing to look out for is if your numerator, the top part of the fraction, factors into something that cancels with the bottom. In that case, it wouldn't affect domain because you aren't actually dividing by anything. For example:

\frac{x^2 - 4}{x-2}

If we factor the top, we see that x^2 - 4 = (x - 2)(x + 2). In this case, we have (x - 2) in both the top and bottom of the fraction, so it cancels out, and from there nothing else is restricting our domain. It would be all real numbers in a case like that.)

8 0
3 years ago
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