Maximum and minimum turning points at (-2|33); (0.4|0.928)
Inflection points at (-1.472|21.195); (0|1); (0.272|0.957)
(y-k)²=4p(x-h)
(h,k) is vertex
and since we got the y term squred, it is facing left or right
when p is positive, then focus is to right of veretx
p is distance from focus to vertex and from vertex to dirextix
y²=-x
(y-0)²=4(-1/4)(x-0)
vertex is (0,0)
p is negative so then focus to left of vertex
so the focus is (-1/4,0)
dirextix is x=1/4
8p-8=-9(2p+5)-9(6-3p)
p=91
I showed the work up there and checked
Answer:s=10.50 and p=27
Step-by-step explanation:
Answer: The answers is alternate interior angles.
Step-by-step explanation: First of all, the questions marks given in the figure are renamed in the attached figure as (a), (b), (c) and (d).
For (a): Since AC is parallel to A'C' and A'D is a transversal for these two parallel lines, so, ∠CDB' = ∠B'A'C', because these are alternate interior angles.
For (b): Since BC is parallel to B'C' and A'B' is a transversal, so ∠BEB' = ∠A'B'C', because these are alternate interior angles.
For (c): Since AB is parallel to A'B' and AD is a transversal, so ∠BAC = ∠CDB', because these are alternate interior angles.
For (d): Since AB is parallel to A'B' and BE is a transversal, so ∠ABC = ∠BEB', because these are alternate interior angles.
Thus, all the questions marks are the reasons that the given angles are equal because they are alternate interior angles.