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Mathematics

2 answers:

Mrrafil [7]3 years ago

8 0

Answer:

$(3x^{2} -6x+11)-(10x^{2} -4x+9)\RightarrowA)-7x^{2} -2x+5$

$(-3x^{2} -5x-3)-(-10x^{2} -7x+2)\RightarrowC)7x^{2} +2-5$

$(12x^{2} +6x-5)-(5x^{2} +8x-12)\Rightarrow B)7x^{2} -2x+7$

$OAmalOHopeO$

son4ous [18]3 years ago

5 0

Answer:

Answer:

Step-by-step explanation:

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The measure of angle X is 18 more than three times the measure of its complement. Find the measure of angle X.

Ymorist [56]

The complement of an angle is 90 minus the angle, or

90 - x = complement angle

if x is 18 more than 3 times it's complement, then

x = 3(complement angle) + 18

We can substitute "90 - x" for the "complement angle" in the second equation:

x = 3(90 - x) + 18

distribute the 3 to the 90 and the x

x = 270 - 3x + 18

add 3x to both sides

4x = 270 - 18
4x = 252
x = 63

the measure of angle x is 63 degrees

6 0

3 years ago

-40-8b=-6(1+7b) what’s the answer

Andre45 [30]

$\text{Hey there!}$

$\mathsf{-40-8b=-6(1+7b)}\\\mathsf{SIMPLIFY\ both\ sides\ of\ your\ equation}\\\mathsf{-40-8b=-6(1+7b)}$

$\mathsf{Distribute\ the\ RIGHT\ side\ of\ the\ equation }\\\mathsf{Distribute [the\ formula\ is: a(b+c)=a(b)+a(c)=ab+ac]}\\\mathsf{-6(1)+(-6)}(7b)\\\mathsf{-6(1)=-6}\\\mathsf{-6(7b)=-42b}\\\mathsf{\rightarrow\ =-6+(-42b)}$

$\mathsf{-40-8b=-6+(-42b)}\\\mathsf{\rightarrow -8b-40=-42b-6}$

$\mathsf{ADD\ by\ 42b\ on\ your\ sides}\\\mathsf{-8b-40+42b=-42b-6+42b}\\\mathsf{SOLVE\ above\ correct\ to\ get\ us\ to\ the\ next\ step!}\\\mathsf{\rightarrow 34b-40=-6}$

$\mathsf{ADD\ by\ 40\ on\ your\ sides}\\\mathsf{34b-40+40=-6+40}\\\mathsf{Cancel\ out\ -40+40\ because\ that\ gives\ the\ result\ of\ 0}\\\mathsf{-6+40=34}\\\mathsf{\rightarrow New\ equation: 34b = 34}$

$\mathsf{DIVIDE\ both\ of\ your\ sides\ by\ 34}\\\mathsf{\dfrac{34b}{34}=\dfrac{34}{34}}\\\\\mathsf{Cancel\ out: \dfrac{34b}{34}\ because\ that\ gives\ you\ the\ result\ of\ 1b}\\\\\mathsf{Keep:\dfrac{34}{34}\ because\ it\ solves\ for\ b}\\\\\mathsf{\dfrac{34}{34}=34\div34=1}$