I will use 0b to refer to binary numbers: ex: 0b1 = 1, 0b10 = 2
0b100 = 4 and 0b11 = 3
4+3 = 7
convert 7 to binary and you get 111.
Hope this helps, and May the Force Be With You!
<span>-Jabba</span>
The program that checks the BMI of a patient is given below:
<h3>THE CODE</h3>
#include <iomanip>
#include <iostream>
#include <math.h>
using namespace std;
// C++ program to illustrate
// how to calculate BMI
float BMI(float height, float weight)
{
float bmi = weight / pow(height, 2);
return bmi;
}
int main()
{
float height = 1.79832;
float weight = 70;
// Function call
float bmi = BMI(height, weight);
cout << "The BMI is " << setprecision(15) << bmi
<< " so ";
// Conditions to find out BMI category
if (bmi < 18.5)
cout << "underweight";
else if (bmi >= 18.5 && bmi < 24.9)
cout << "Healthy";
else if (bmi >= 24.9 && bmi < 30)
cout << "overweight";
else if (bmi >= 30)
cout << "Suffering from Obesity";
return 0;
}
// This code is contributed by aarohirai2616.
<h3>Output: </h3>
The BMI is 21.64532402096181 so Healthy
Read more about algorithms here:
brainly.com/question/24953880
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What did you do when you got to school tomorrow and then again I don't want it
Answer:
=((SUM(PUT RANGE OF MOTHLY EXPENSES HERE)*12)+SUM(PUT RANGE OF YEARLY EXPENSES HERE))/12
Explanation:
Adds all of the Monthly Expenses : SUM(PUT RANGE OF MOTHLY EXPENSES HERE)
Multiplies the result by 12: *12
Then adds all of the Yearly Expenses to the product of Steps 1 and 2 : SUM(PUT RANGE OF YEARLY EXPENSES HERE)
Divides this new sum by 12: /12
=((SUM(PUT RANGE OF MOTHLY EXPENSES HERE)*12)+SUM(PUT RANGE OF YEARLY EXPENSES HERE)/12)
