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3 years ago

can someone please help me. my grade is very low in this class although i have no idea how to do this PLEASE HELP!!

Mathematics

2 answers:

Minchanka [31]3 years ago

8 0

Answer: How to solve equations

Step-by-step explanation:

You have to use Pemdas the order of operations to solve these types of equations.

Parenthesis,Exponents,multiplication,Division,Addition,subtraction.

Multiplication and division fit in a group left to right.

Addition and subtraction come last but depends on which comes first left to right.

Here you first have to use the distributive property.

3(y+5)=39 multiply 3 times y that gives you 3y. Then multiply 3 times 5 that gives you 15 . So, now you have simplified the left side of the equal sign so you have 3y+15=39 now subtract 15 from both sides and you get 3y=24 then you divide both sides by 3 to get y=8. What I just went over you do again and again to solve all these types of equations. Your trying to solve for the variable so you try to get y or m or n or any variable by itself.

kondor19780726 [428]3 years ago

3 0

Answer:

download symbolab or download photo math it gets I covered on most of that your grade should go up

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3 years ago

If the average speed of a garden snail is 0.025 miles per hour and one inch is approximately 2.54 centimeters, how many minutes

BaLLatris [955]

Snail takes 1.5 minutes to travel around one meter

<u>Solution:</u>

Given, the average speed of a garden snail is 0.025 miles per hour

And one inch is approximately 2.54 centimeters,

We have to find how many minutes would it take a garden snail to travel one meter?

Now, let us convert the speed in miles per hour to meters per minute

Then, speed = 0.025 miles per hour

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= 0.025 x 1609.34 / 60 meters per minute

$\begin{array}{l}{=\frac{0.025 \times 1609.34}{60} \text { meters per minute }} \\\\ {=\frac{40.2335}{60} \text { meters per minute }}\end{array}$

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3 0

3 years ago

Read 2 more answers

What is the perimeter of the trapezoid with vertices Q(8, 8), R(14, 16), S(20, 16), and T(22, 8)? Round to the nearest hundredth

EleoNora [17]

Check the picture below.

so... you can pretty much see how long RS and QT are, you can just count the units off the grid.

now, let's find QR's length

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&Q&(~ 8 &,& 8~) 
% (c,d)
&R&(~ 14 &,& 16~)
\end{array}~~ 
% distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
QR=\sqrt{(14-8)^2+(16-8)^2}\implies QR=\sqrt{6^2+8^2}
\\\\\\
QR=\sqrt{36+64}\implies QR=\sqrt{100}\implies QR=10$

and let's also find the length for ST

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&S&(~ 20 &,& 16~) 
% (c,d)
&T&(~ 22 &,& 8~)
\end{array}~ 
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
ST=\sqrt{(22-20)^2+(8-16)^2}\implies ST=\sqrt{2^2+(-8)^2}
\\\\\\
ST=\sqrt{4+64}\implies ST=\sqrt{68}\implies ST=\sqrt{4\cdot 17}
\\\\\\
ST=\sqrt{2^2\cdot 17}\implies ST=2\sqrt{17}$

so, add the lengths of all sides, and that's the perimeter of the trapezoid.

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3 years ago

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