Answer:
Probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.
Step-by-step explanation:
We are given that the diameters of ball bearings are distributed normally. The mean diameter is 106 millimeters and the standard deviation is 4 millimeters.
<em>Firstly, Let X = diameters of ball bearings</em>
The z score probability distribution for is given by;
Z =
~ N(0,1)
where,
= mean diameter = 106 millimeters
= standard deviation = 4 millimeter
Probability that the diameter of a selected bearing is greater than 111 millimeters is given by = P(X > 111 millimeters)
P(X > 111) = P(
>
) = P(Z > 1.25) = 1 - P(Z
1.25)
= 1 - 0.89435 = 0.1056
Therefore, probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.
This is a geometric series with first term e^3 and common ratio e^-2. The sum of it will be
.. e^3/(1 -e^-2) ≈ 23.229277815766...
Answer:
rational function
Step-by-step explanation:
That would be a "rational function;" it's the "ratio" of two polynomial functions, with the understanding that the denominator may not be zero.
Answer:
$1.63
Step-by-step explanation:
Divide 4.89 by 3
Answer: $1.63
Simple
Hope it helps ♥️♥️
Answer:
sry i dont know
Step-by-step explanation:
lolz