i work at my uncle’s restaurant but idr work
3/20 is the same as 15/100 or 15%
so 10×3/20 would be the same as 10×15% or 150%
Is that what you were asking?
g(x) = (1/4)x^2 . correct option C) .
<u>Step-by-step explanation:</u>
Here we have , 
and we need to find g(x) from the graph . Let's find out:
We have , . From the graph we can see that g(x) is passing through point (2,1 ) . Let's substitute this point in all of the four options !
A . g(x) = (1/4x)^2
Putting (2,1) in equation g(x) = (x/4)^2 , we get :
⇒ 
⇒ 
Hence , wrong equation !
B . g(x) = 4x^2
Putting (2,1) in equation g(x) = 4x^2 , we get :
⇒ 
⇒ 
Hence , wrong equation !
C . g(x) = (1/4)x^2
Putting (2,1) in equation g(x) = (1/4)x^2 , we get :
⇒ 
⇒ 
Hence , right equation !
D . g(x) = (1/2)x^2
Putting (2,1) in equation g(x) = (1/2)x^2 , we get :
⇒ 
⇒ 
Hence , wrong equation !
Therefore , g(x) = (1/4)x^2 . correct option C) .
Y=-5x-2
-2= y-intercept
-5x= slope
find y-intercept on a graph, make a dot.
then use slope from y-intercept dot, make another dot.
Draw line.
Is it a positive or Negative slope?
Hope that helps.
9514 1404 393
Answer:
21.25 seconds
Step-by-step explanation:
In miles per second, the speed of the jet is ...
(720 mi/h)/(3600 s/h) = 1/5 mi/s
The speed of the sound is the same:
(1 mi)/(5 s) = 1/5 mi/s
Then the rate of closure between the airplane and the sound is ...
(1/5 mi/s) +(1/5 mi/s) = 2/5 mi/s
To find the time required to close a gap of 8 1/2 miles, we can use the relation ...
time = distance/speed
time = (8.5 mi)/(0.4 mi/s) = 21.25 s
The pilot will hear the thunder 21.25 seconds after the flash.
