She would have used 1200 messages in all by the month of August.
Step-by-step explanation:
Messages allowed per month = 150
There will be 8 months starting from January to August, therefore,
Time period = 8 months
Messages in 8 months = Messages per month * Time period
She would have used 1200 messages in all by the month of August.
Keywords: Multiplication
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Answer:
yes, it is equivalent!!
Step-by-step explanation:
6(3x + 1) = 18x + 6
9x + 6 + 9x combined will also equal 18x + 6
Answer:
The focus of the parabola is at the point (0, 2)
Step-by-step explanation:
Recall that the focus of a parabola resides at the same distance from the parabola's vertex, as the distance from the parabola's vertex to the directrix, and on the side of the curve's concavity. In fact this is a nice geometrical property of the parabola and the way it can be constructed base of its definition: "All those points on the lane whose distance to the focus equal the distance to the directrix."
Then, the focus must be at a distance of two units from the vertex, (0,0), on in line with the parabola's axis of symmetry (x=0), and on the positive side of the y-axis (notice the directrix is on the negative side of the y-axis. So that puts the focus of this parabola at the point (0, 2)
What’s the items number. ? When rounding everything in front of the decimal find the place value it wants you to round then if it’s 5 or below round the the lowest whole number. If it’s behind a decimal you would do the same thing. It’s the number is higher than 5 round it up.
Answer:
Jaden has to plant the geranium in the circumcentre of the triangular yard in order such that it is equidistant from all its vertices.
Step-by-step explanation:
In Jaden’s yard, there is a triangular garden patch. He wants to plant a geranium in the patch at a point equidistant from all its vertices.
<em>" The CIRCUMCENTER (C) of a triangle is the point in the plane equidistant from the three vertices of the triangle "</em>
Hence Jaden has to plant the geranium in the circumcentre of the triangular yard in order such that it is equidistant from all its vertices.
