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liberstina [14]
3 years ago
5

Please please help me with those questions

Mathematics
1 answer:
Illusion [34]3 years ago
8 0

Answer:

1. acute

2. obtuse

3. obtuse

4.reflex

5.acute

6. right

7. reflex

8. obtuse

9. reflex

10. straight

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Guys Can you please help me with this math
Likurg_2 [28]

Answer:

You can buy up to 6 candy bars with a soda

Step-by-step explanation:

7$-2.50$=4.50$

4.50$ / .75$ = 6

4 0
3 years ago
Find the slope of the line that passes through the points (1,6) and (5,6)
Oksi-84 [34.3K]

Answer:

m=0 (m is the slope)

Step-by-step explanation:

m=y2-y1/x2-x1

m=6-6/1-5

m=0/4

m=0

*Note: If the zero is in the denominator (on the bottom) the slope is undefined (UND).

8 0
3 years ago
A segment with endpoint M Left parenthesis 5 comma 9 right parenthesis and N Left parenthesis 4 comma 3 right parenthesis is rot
mario62 [17]
Refer to the diagram below

If we draw a line that connects the center of rotation to one of the points, say point N, and take this line as the 0° position, then we need three 'turn' of 90° to get to 270°.

Coordinate of N' (-3, 4)
Coordinate of M' (-9, 5)

3 0
3 years ago
Find all zeros of ƒ(x) = 2x^4 – 72x^2. Then determine the multiplicity at each zero. State whether the graph will touch or cross
AleksandrR [38]

Answer: See below

Step-by-step explanation:

<u>To find the factor,</u>

f(x) = 0

\begin{aligned}&2 x^{4}-72 x^{2}=0 \\&2 x^{2}\left(x^{2}-36\right)=0 \\&x^{2}\left(x^{2}-36\right)=0 \\&x \times x \times(x-6) \times(x+6)=0 \\&\mathrm{x}=0,0,6,-6\end{aligned}

<u>So,</u>

x = 0 multiplicity 2

x = -6 multiplicity 1

x = 6 multiplicity 1

For an even multiplicty, the graph touches the x-axis, and for an odd multiplicty, the graph crosses the x-axis

<u>Therefore,</u>

x = 0 multiplicty 2, Touch

x = -6 multiplicty 1, Cross

x = 6 multiplicty 1, Cross

7 0
2 years ago
What is f(6) for the quadratic function​
Feliz [49]
Usually when you see f(x) or as yours is f(6) f with parenthesis is just a fancy way of saying y= so basically you plug six in for the x values of your question
8 0
3 years ago
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