For rigt triangle with legs legnth a and b and hypotnuse legnth c
a^2+b^2=c^2
we are given
larger leg is 3 longer than smaller leg
hypotnuse is 6 longer than smaller
find smaller
ok so
first pick a smaller leg
lets say b is smaller
longer leg is 3 more than shorter leg
a is 3 more than b
a=3+b
and
hypontuse is 6 more than shorter
c=6+b
sub 3+b for a and 6+b for c in oroiginal equation'
a^2+b^2=c^2
(3+b)^2+b^2=(6+b)^2
9+6b+b^2+b^2=36+12b+b^2
2b^2+6b^2+9=b^2+12b+36
minus (b^2+12b+36) from both sides
b^2-6b-27=0
factor
(b-9)(b+3)=0
set equal to zero
b-9=0
b=9
b+3=0
b=-3
fasle, legnths cannot be negative
answer is shorter side=9 cm
Answer:
x > 8.125 or 8 & 1/8
Step-by-step explanation:
8( -x - 7) > 16
-8x - 49 > 16
+ 49 + 49
-8x > 65
x > 8.125 or 8 & 1/8
A contraction would make the image smaller.
A negative number reflects the image and changes the size based on the number.
To make an image smaller the factor needs to be less than 1
so -0.5 and 0.5 would make the image smaller since 0.5 is less than 1.
The equation that you should use to solve this is (13 + 1/4) - (6 + 2/3) = 6 and 7/12
Answer:
y=5x-6
Step-by-step explanation:
Comparing y=5x-6 with y=mx+c,the slope is 5 and y intercept is-6