For the answer to the question above, this question is incomplete. I've answered this question before.
Is it like this?
V = (1/3) * (area of the base) * height
<span>If you have a pyramid with a square base, you just multiply the length of both sides together. For example, if the pyramid was 9 inches on a side, the area of the base is 9 * 9 = 81 sq. inches. </span>
<span>Then you multiply that by the height and finally take 1/3 of the result. For example, if the pyramid was 10 inches high, you multiply 81 sq. inches x 10 inches = 810 cubic inches. But you have to remember to take a third of that result. 810 cubic inches / 3 = 270 cubic inches.
</span>I hope this helps
Answer:
15•4 mm
Step-by-step explanation:
using sine rule
a÷ sinA=c ÷sinC
15•4÷sin90=0•5÷sinC
sinC =0•5 × sin90 ÷ 15•4
C =1•9°
A+B+C= 180
90+B+1•9=180
B= 88•2°
b÷sinB = a÷sinA
b÷sin88•2= 15•4÷sin90
b=sin88•2 ×15•4 ÷sin90
b =15•39
to 1 dp
b =15•4 mm
Answer:
![\left[\begin{array}{ccc}3&0&0\\0&3&0\\0&0&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%260%260%5C%5C0%263%260%5C%5C0%260%263%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
In order to find out the resulting matrix, we will have to multiply the identity matric and the scalar 3:
The 3x3 identity matrix is:
![\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%260%5C%5C0%261%260%5C%5C0%260%261%5Cend%7Barray%7D%5Cright%5D)
Multiplying with scalar 3:
![3\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]](https://tex.z-dn.net/?f=3%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%260%5C%5C0%261%260%5C%5C0%260%261%5Cend%7Barray%7D%5Cright%5D)
The scalar will be multiplied by each element of the matrix.
Multiplying zeros with scalar 3 will give us zero. So the resulting matrix will be:
![\left[\begin{array}{ccc}3*1&0&0\\0&3*1&0\\0&0&3*1\end{array}\right] = \left[\begin{array}{ccc}3&0&0\\0&3&0\\0&0&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%2A1%260%260%5C%5C0%263%2A1%260%5C%5C0%260%263%2A1%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%260%260%5C%5C0%263%260%5C%5C0%260%263%5Cend%7Barray%7D%5Cright%5D)
So the resultant matrix will be a scalar matrix with 3 at diagonal positions..
Answer:
<h2>135</h2>
Step-by-step explanation:

Answer:
A
Step-by-step explanation: