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never [62]
3 years ago
7

Use substitution to solve the system of equations. How many solutions are there? 1/2x − 1/3y = 5 x = 2/3y + 10

Mathematics
1 answer:
Vadim26 [7]3 years ago
7 0

Answer:

2 solutions cuz

2 variable are there

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Eighty eighths in cups
Tamiku [17]

if you have 88 tablespoons and you convert them into cups you would have 5.5 then you would convert that into a fraction which would be 5 1/2

5 0
3 years ago
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How do you simplify (-5x^5+14)-(11x^2+1+11x^5)
lord [1]
(-5x ⁵+14)-(11x ²+1+11x ⁵)
Like terms: -5x ⁵-11x ⁵ = -16x ⁵
Like terms also: 14-1 = 13
Simplified all together: -16x ⁵ - 11x ²+ 13
(Always put highest degree first)
6 0
3 years ago
12x+7&lt;−11 OR 5x−8&gt;40<br> solve for x
kipiarov [429]

Answer:

x < -1.5 U x > 9.6

Step-by-step explanation:

12x + 7 < -11

x < -1.5

5x - 8 > 40

5x > 48

x > 9.6

6 0
3 years ago
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8z+12+3
yarga [219]

Answer:

8z+15

Step-by-step explanation:

7 0
3 years ago
Situation:
Gala2k [10]

Answer:

5.5 days (nearest tenth)

Step-by-step explanation:

<u>Given formula:</u>

\sf N=N_0e^{-kt}

  • \sf N_0 = initial mass (at time t=0)
  • N = mass (at time t)
  • k = a positive constant
  • t = time (in days)

Given values:

  • \sf N_0 = 11 g
  • k = 0.125

Half-life:  The <u>time</u> required for a quantity to reduce to <u>half of its initial value</u>.

To find the time it takes (in days) for the substance to reduce to half of its initial value, substitute the given values into the formula and set N to half of the initial mass, then solve for t:

\begin{aligned}\sf N & = \sf N_0e^{-kt}\\\\\implies \sf \dfrac{11}{2} & = \sf 11e^{-0.125t}\\\\\sf \dfrac{1}{2} & = \sf e^{-0.125t}\\\\\sf \ln \left(\dfrac{1}{2}\right) & = \sf \ln e^{-0.125t\\\\\sf \ln \left(\dfrac{1}{2}\right) & = \sf -0.125t \ln e\\\\\sf \ln \left(\dfrac{1}{2}\right) & = \sf -0.125t(1)\\\sf t & = \sf \dfrac{\ln \left(\dfrac{1}{2}\right)}{-0.125}\\\\\sf t & = \sf 5.545177444...\\\\\sf t & = \sf 5.5\:\:days\:\:(nearest\:tenth)\end{aligned}

Therefore, the substance's half-life is 5.5 days (nearest tenth).

Learn more about solving exponential equations here:

brainly.com/question/28016999

5 0
2 years ago
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