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2 years ago

Find the dimensions of a box that will hold twice as many cubes as a box that is 4 by 2 by 9

Mathematics

2 answers:

fiasKO [112]2 years ago

5 0

Yah i think he is right because 4(2)(9)is 72 (2) is 144 if you are wondering h9w he got it.

Murljashka [212]2 years ago

3 0

You can't tell what its dimensions must be. All you can say for sure is that their product is 144.

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5.37 + x =12.89 explanation please it’s two step equation

Wewaii [24]

Answer:

7.52

Step-by-step explanation:

5.37 + x = 12.89

In order to solve this equation, we must isolate the variable, x.

1.) To do this, subtract 5.37 on both sides of the equation.

5.37 + x = 12.89

-5.37 -5.37

x = 7.52

Therefore, x = 7.52

6 0

2 years ago

Read 2 more answers

6) The length of a rectangle is 2 inches more than twice its width. Write an

34kurt

Answer:

2w + 2

Step-by-step explanation:

Width = w

Twice its width = 2*w =2w

2 inches more than twice its width = 2w + 2

Length = 2w + 2

5 0

3 years ago

QUESTION 3 Toyota provides an option of a sunroof and side airbag package for its Corolla model. This package costs $1400. Assum

Orlov [11]

Answer:

n=601

Step-by-step explanation:

Formula used:

$n=z(\frac{\alpha }{2})^2\frac{p(1-p) }{E^2}$

Solution:

$n=z(\frac{\alpha }{2})^2\frac{p(1-p) }{E^2}$

Where,

$\frac{\alpha }{2}=0.025$

As there is no previous estimate for p

Then, p=0.5

Here on using the table

$z(\frac{\alpha }{2}) =1.959963985$

Also,

E=0.04

p=0.5

Thus,

n=600.2279407

On approximating the value,

n=601

6 0

2 years ago

The daily dinner bills in a local restaurant are normally distributed with a mean of $28 and a standard deviation of $6. What ar

Degger [83]

Answer:

The minimum value of the bill that is greater than 95% of the bills is $37.87.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 28, \sigma = 6$