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3 years ago

What is the next step to solve this equation? n - 4 = -2

Mathematics

1 answer:

Alex Ar [27]3 years ago

8 0

Answer:

add 4 to both sides of the equation

Step-by-step explanation:

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Help appreciated please and thank you

meriva

Answer:

D. $\frac{4 \sqrt{33} }{33}$

Step-by-step explanation:

$\tan \alpha = \frac{4}{ \sqrt{33} } \\ = \frac{4}{ \sqrt{33} } \times \frac{ \sqrt{33} }{ \sqrt{33} } \\ \\ = \frac{4 \sqrt{33} }{ {( \sqrt{33)} }^{2} } \\ \\ \tan \alpha = \frac{4 \sqrt{33} }{33}$

8 0

3 years ago

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What undefined term defines an parellel line

ss7ja [257]

Parallel lines- lines that can go on and on without touching each other.

6 0

4 years ago

Help please solve for Y

Valentin [98]

Answer:

y=13

Step-by-step explanation:

8 0

3 years ago

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Uh i need help bc i cant get the question correct

Klio2033 [76]

Answer:

164

Step-by-step explanation:

Finding the Surface Area :

Area (2 triangles) + Base rectangle + Left rectangle + Right rectangle
2 x 1/2 x 4 x 5 + 9 x 5 + 6 x 9 + 5 x 9
20 + 45 + 54 + 45
65 + 99
164 cm²

6 0

2 years ago

Read 2 more answers

What is the area of rhombus ABCD? Enter your answer in the box. Do not round at any steps.

Mrac [35]

Answer:

Area of the rhombus ABCD = 16 square units

Step-by-step explanation:

Area of a rhombus = $\frac{1}{2}(\text{Diagonal 1})(\text{Diagonal 2})$

From the graph attached,

Diagonal 1 = Distance between the points A and C

Diagonal 2 = Distance between the points B and D

Length of a segment between (x₁, y₁) and (x₂, y₂) = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^2 }$

Diagonal 1 (AC) = $\sqrt{(4-0)^2+(-1+1)^2}$ = 4 units

Diagonal 2(BD) = $\sqrt{(2-2)^2+(3+5)^2}$ = 8 units

Now area of the rhombus ABCD = $\frac{1}{2}(\text{AC})(\text{BD})$

= $\frac{1}{2}\times 4\times 8$

= 16 units²

Therefore, area of the given rhombus is 16 units².

5 0

3 years ago