15/8-4/5/1+(15/8)(4/5)

$ The sum of twe numbers is 42. Their difference is 16.

tresset_1 [31]

Answer:

x = 29

y = 13

Step-by-step explanation:

Write 2 equations:

x + y = 42

x - y = 16

Isolate x in the first equation:

x = 42 - y

Substitute this in for x in the second equation:

42 - y - y = 16

42 - 2y = 16

solve for y:

-2y = -26

y = 13

Plug in 13 for y in either equation:

x + 13 = 42

Solve for x:

x = 29

3 0

3 years ago

An example of an addition problem in which you would and would not group the addends different to add

murzikaleks [220]

I dont think so. and you should add and then reseporate the groups.

5 0

3 years ago

A quality control engineer at a potato chip company tests the bag filling machine by weighing bags of potato chips. Not every ba

Ahat [919]

Answer:

$z=\frac{0.21 -0.15}{\sqrt{\frac{0.15(1-0.15)}{100}}}=1.68$

Step-by-step explanation:

Information provided

n=100 represent the random sample taken

X=21 represent the number of bags overfilled

$\hat p=\frac{21}{100}=0.21$ estimated proportion of overfilled bags

$p_o=0.15$ is the value that we want to test

z would represent the statistic

Hypothesis

We need to conduct a hypothesis in order to test if the true proportion of overfilled bags is higher than 0.15.:

Null hypothesis: $p =0.7$

Alternative hypothesis: $p > 0.15$

The statistic for this case is:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

And replacing the info given we got:

$z=\frac{0.21 -0.15}{\sqrt{\frac{0.15(1-0.15)}{100}}}=1.68$

5 0

3 years ago

Solve the equation for b.

Mkey [24]

Answer:

Move all terms to the left side and set equal to zero. Then set each factor equal to zero.

b = M /4 + 9 x

7 0

3 years ago

Read 2 more answers

Three components are randomly sampled, one at a time, from a large lot. As each component is selected, it is tested. If it passe

satela [25.4K]

Answer:

The probability of SFS and SSF are same, i.e. P (SFS) = P (SSF) = 0.1311.

Step-by-step explanation:

The probability of a component passing the test is, P (S) = 0.79.

The probability that a component fails the test is, P (F) = 1 - 0.79 = 0.21.

Three components are sampled.

Compute the probability of the test result as SFS as follows:

P (SFS) = P (S) × P (F) × P (S)

$=0.79\times0.21\times0.79\\=0.131061\\\approx0.1311$

Compute the probability of the test result as SSF as follows:

P (SSF) = P (S) × P (S) × P (F)

$=0.79\times0.79\times0.21\\=0.131061\\\approx0.1311$

Thus, the probability of SFS and SSF are same, i.e. P (SFS) = P (SSF) = 0.1311.

7 0

4 years ago