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Anarel [89]
3 years ago
13

Use the graph to answer the question. On a coordinate plane, a curve starts at (negative 1, negative 1) and curves down through

(negative 4, negative 2). A line goes from closed circle (negative 1, 3) and goes to open circle (3, 7), and then curves down to (5, 3) and up through (7, 7). A closed circle is at (3, negative 1). Using limits, for which value of x is the function continuous? Check all that apply. –2 –1 0 3 5
Mathematics
1 answer:
Softa [21]3 years ago
5 0

Answer:

A, C, and E

Step-by-step explanation:

-2, 0, and 5

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3 years ago
On a coordinate plane, a parabola opens up. It goes through (negative 2, 4), has a vertex at (0.25, negative 6), and goes throug
Oksana_A [137]

Answer:

The function has two x-intercepts.

The vertex of the function is (one-quarter, negative 6 and one-eighth).

Step-by-step explanation:

Given that the vertex is located at (0.25, -6)  and the parabola opens up, the function has two x-intercepts.

f(x) = 2x² - x - 6 has the following coefficients:

a = 2

b = -1

c = -6

x-coordinate of the vertex is:

x = -b/(2a)

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y-coordinate of the vertex is:

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3 0
3 years ago
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Answer:

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Step-by-step explanation:

5 0
3 years ago
Help me please thank you
Usimov [2.4K]

Answer:

x = 7

Step-by-step explanation:

5x + 9 = 6x + 2

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-x = -7

x = 7

probe:

5*7 + 9 = 6*7 + 2

35 + 9 = 42 + 2 = 44

7 0
3 years ago
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