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UkoKoshka [18]
3 years ago
9

The sum of one-third of a number and three-fourths of the number exceeds that number by one.

Mathematics
2 answers:
ira [324]3 years ago
8 0

Answer:

The correct answer is last option

1/3n + n 3/4= n + 1

Step-by-step explanation:

It is given that,the sum of one-third of a number and three-fourths of the number exceeds that number by one

<u>To find the correct option</u>

Let 'n' be the number, one- third of the number = 1/3(n)

three - fourths of the number = 3/(4n)

Therefore the equation becomes,

1/(n) + 3/4(n)  = n + 1

Therefore the correct answer is last option

victus00 [196]3 years ago
6 0

The answer would be...

1/3n + 3/4n = n + 1

^^^That would be the last option

Hope this helped!

~Just a girl in love with Shawn Mendes

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Please explain how to solve this (<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7Ba%5E5%20b%5E3%7D%20" id="TexFormula1" ti
olchik [2.2K]
2 is the base and (\sqrt[4][a^5 b^3]) is the exponent.

the 4 is called an index and it means to fi d the fourth root of the expression under the (\sqrt[][text]) symbol.\\a fourth root is a factor that was multiplied four times. ex: 2*2*2*2=16. the fourth root of 16 is two. \\when you do square roots, you take the number representing the factor out of the radical. anything else that is not a square root stays under. ex: \\([tex]\sqrt[9][text])\\([tex]\sqrt[3*3*3][text]) there is one set of two 3's so\\([tex]3\sqrt[3][text])\\with a fourth root, you look for groups of four. the symbol of that group is placed outside the radical. anything else stays in.\\ ([tex]\sqrt[4][a^5 b^3])

(\sqrt[4][a*a*a*a*a*b*b*b]) there is one group of 4 a's so

(a\sqrt[4][a* b^3])

there really isn't anything else to do to simplify the expression
5 0
3 years ago
132 boys to 89 girls what's the ratio
Dafna1 [17]
132:89 is the answer
6 0
3 years ago
A halogen-lighting manufacturer packs 64 halogen lamps ink a cube-shaped container. the manufacturer has been asked by his distr
pishuonlain [190]
64 divided by 8 = 8

So you're answer would be 8
4 0
3 years ago
Fifteen minutes past eight in the evening on a 24 hour clock​
anastassius [24]

Answer: The time is 20:15 on a military time clock.

Step-by-step explanation:

4 0
2 years ago
Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.
likoan [24]

Answer:

Thus, the two root of the given quadratic equation x^2+4=6x is 5.24 and 0.76 .

Step-by-step explanation:

Consider, the given Quadratic equation, x^2+4=6x

This can be written as ,  x^2-6x+4=0

We have to solve using quadratic formula,

For a given quadratic equation ax^2+bx+c=0 we can find roots using,

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}  ...........(1)

Where,  \sqrt{b^2-4ac} is the discriminant.

Here, a = 1 , b = -6 , c = 4

Substitute in (1) , we get,

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

\Rightarrow x=\frac{-(-6)\pm\sqrt{(-6)^2-4\cdot 1 \cdot (4)}}{2 \cdot 1}

\Rightarrow x=\frac{6\pm\sqrt{20}}{2}

\Rightarrow x=\frac{6\pm 2\sqrt{5}}{2}

\Rightarrow x={3\pm \sqrt{5}}

\Rightarrow x_1={3+\sqrt{5}} and \Rightarrow x_2={3-\sqrt{5}}

We know \sqrt{5}=2.23607(approx)

Substitute, we get,

\Rightarrow x_1={3+2.23607}(approx) and \Rightarrow x_2={3-2.23607}(approx)

\Rightarrow x_1={5.23607}(approx) and \Rightarrow x_2=0.76393}(approx)

Thus, the two root of the given quadratic equation x^2+4=6x is 5.24 and 0.76 .

7 0
3 years ago
Read 2 more answers
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