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3 years ago

Plsss help this is hard for me

Mathematics

1 answer:

soldi70 [24.7K]3 years ago

8 0

Diameter is radius plus radius so its 14. Circumference is radius times pi which is 3. 14 so the answer for Circumference is 43.98.
Area is 153.94 the formula is A= nr to the power of two

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Plss help, ill give brainiest

White raven [17]

Answer:

Step-by-step explanation:

Cylinder volume= V = π r ^2 h

So you times Pie by the radius (diametre divided by two- 3.5) you then square this. After that, times it by the height (10)

So the volume is 384.85.

You then find 30% of this, so times 384.85 by 30%.

You then get an answer of 115.455, and this is equal to A.

I hope this helps, have a lovely day.

5 0

2 years ago

GIVING BRAINLESS HELP!!

aliina [53]

Jessica bought 2.25 yards more material than Derek. Hope this helped!

4 0

3 years ago

What is the slope of the line that passes through the points (10,5) and (9,5)? Write

Alex_Xolod [135]

Answer:

slope of line is 0.

Step-by-step explanation:

Slope of a line passing through (x1,y1) and (x2,y2) is given by

m = (y2-y1)/(x2-x1)

Given points are (10,5) and (9,5)

thus

slope = (5-5)/(9-10) = 0/-1 = 0

Thus, slope of line is 0.

When slope of line is zero it means that the line the which passes through given point is parallel to x-axis.

4 0

3 years ago

-3x+4>-23 what is the answer I need help

Dmitrij [34]

X<9
The answer is x<9 because you first subtract 4 from both sides then divide both sides by -3. Which then would give you 9.

5 0

3 years ago

A manufacturer of Christmas light bulbs knows that 10% of these bulbs are defective. It is known that light bulbs are defective

Inessa05 [86]

Answer:

(a) P(X $\leq$ 20) = 0.9319

(b) Expected number of defective light bulbs = 15

Step-by-step explanation:

We are given that a manufacturer of Christmas light bulbs knows that 10% of these bulbs are defective. It is known that light bulbs are defective independently. A box of 150 bulbs is selected at random.

Firstly, the above situation can be represented through binomial distribution, i.e.;

$P(X=r) = \binom{n}{r} p^{r} (1-p)^{2} ;x=0,1,2,3,....$

where, n = number of samples taken = 150

r = number of success

p = probability of success which in our question is % of bulbs that

are defective, i.e. 10%

Now, we can't calculate the required probability using binomial distribution because here n is very large(n > 30), so we will convert this distribution into normal distribution using continuity correction.

So, Let X = No. of defective bulbs in a box

Mean of X, $\mu$ = $n \times p$ = $150 \times 0.10$ = 15

Standard deviation of X, $\sigma$ = $\sqrt{np(1-p)}$ = $\sqrt{150 \times 0.10 \times (1-0.10)}$ = 3.7

So, X ~ N( $\mu = 15, \sigma^{2} = 3.7^{2})$

Now, the z score probability distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

(a) Probability that this box will contain at most 20 defective light bulbs is given by = P(X $\leq$ 20) = P(X < 20.5) ---- using continuity correction

P(X < 20.5) = P( $\frac{X-\mu}{\sigma}$ < $\frac{20.5-15}{3.7}$ ) = P(Z < 1.49) = 0.9319

(b) Expected number of defective light bulbs found in such boxes, on average is given by = E(X) = $n \times p$ = $150 \times 0.10$ = 15.

5 0

3 years ago