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Ratling [72]
3 years ago
13

Will someone please help me with these questions.

Mathematics
1 answer:
gladu [14]3 years ago
3 0

Hello,

Please, see the attached files.

Thanks.

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An equation parallel and perpendicular to 4x+5y=19
UNO [17]

Answer:

Parallel line:

y=-\frac{4}{5}x+\frac{9}{5}

Perpendicular line:

y=\frac{5}{4}x-\frac{1}{2}

Step-by-step explanation:

we are given equation 4x+5y=19

Firstly, we will solve for y

4x+5y=19

we can change it into y=mx+b form

5y=-4x+19

y=-\frac{4}{5}x+\frac{19}{5}

so,

m=-\frac{4}{5}

Parallel line:

we know that slope of two parallel lines are always same

so,

m'=-\frac{4}{5}

Let's assume parallel line passes through (1,1)

now, we can find equation of line

y-y_1=m'(x-x_1)

we can plug values

y-1=-\frac{4}{5}(x-1)

now, we can solve for y

y=-\frac{4}{5}x+\frac{9}{5}

Perpendicular line:

we know that slope of perpendicular line is -1/m

so, we get slope as

m'=\frac{5}{4}

Let's assume perpendicular line passes through (2,2)

now, we can find equation of line

y-y_1=m'(x-x_1)

we can plug values

y-2=\frac{5}{4}(x-2)

now, we can solve for y

y=\frac{5}{4}x-\frac{1}{2}


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Raul can read 12 pages in half an hour​
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