Answer:
expression: (30/t) - 10
evaluation: 30/2 - 10 = 5
Step-by-step explanation:
Answer:
√(196a^2b^5) = 14ab^2√b
Step-by-step explanation:
Alternate form assuming a and b are positive:
Answer:
The equation is 
Step-by-step explanation:
Let the quadratic function be

The point (-4,9) must satisfy this function,


The point (0,-7) must also satisfy this function,


The point (1,-1) must also satisfy this function,


We put equation 2 into equation 1 to get;



We again put equation 2 into equation 3 to get;


We add equation 5 and 6 to get;


We put
into equation 6 to get;



The equation is therefore 
Answer:
-3000000000
Step-by-step explanation:
Math
Given tangent, ZN, to the circle and the arc
= 280°, we have that
the angle formed by the chord BZ and the tangent ZN, ∠BZN is 50°
<h3>Which method can be used to find ∠BZN?</h3>
The given parameters are;
A tangent to the circle O = ZN

Required:
Angle ∠BZN
Solution;
Please find attached the drawing of the circle and tangent
From the drawing, we have;
∠BOZ = 360° - 280° = 80°
ΔBOZ is an isosceles triangle, which gives;
∠BZO = ∠ZBO

∠OZN = 90° (by definition of a tangent)
∠OZN = ∠BZO + ∠BZN
∠BZN = ∠OZN - ∠BZO
Which gives;
∠BZN = 90° - 40° = 50°
- The measure of angle ∠BZN =<u> 50°</u>
Learn more about tangents to a circle here:
brainly.com/question/14561226