Suppose your club is selling to
1 answer:
You might be interested in
Let the numbers be 1k, 2k , and 3k respectively
Since the sum of their cubes is 4500,
(1k)³+(2k)³+(3k)³=4500
--> k³(36)= 4500
--> k = 5
Hence, the numbers are: 5,10 and 15 respectively
Since the sum of their cubes is 4500,
(1k)³+(2k)³+(3k)³=4500
--> k³(36)= 4500
--> k = 5
Hence, the numbers are: 5,10 and 15 respectively