Answer:
The t value for 99% CI for 21 df is 2.831.
The critical value that should be used in constructing the confidence interval is (64.593, 86.407).
Step-by-step explanation:
Now the sample size is less than 30 and also population standard deviation is not known.
Then we will use t distribution to find CI
t value for 99% CI for 21 df is TINV(0.01,21)=2.831
The margin of error is
Hence CI is
Answer:
The answer is going to be
B. 25units
Answer:
c
Step-by-step explanation:
L = rc
= 26.9 * 9*3.14 / 5
= 152.04 to nearest 1/100