Hi there!

To find the indefinite integral, we must integrate by parts.
Let "u" be the expression most easily differentiated, and "dv" the remaining expression. Take the derivative of "u" and the integral of "dv":
u = 4x
du = 4
dv = cos(2 - 3x)
v = 1/3sin(2 - 3x)
Write into the format:
∫udv = uv - ∫vdu
Thus, utilize the solved for expressions above:
4x · (-1/3sin(2 - 3x)) -∫ 4(1/3sin(2 - 3x))dx
Simplify:
-4x/3 sin(2 - 3x) - ∫ 4/3sin(2 - 3x)dx
Integrate the integral:
∫4/3(sin(2 - 3x)dx
u = 2 - 3x
du = -3dx ⇒ -1/3du = dx
-1/3∫ 4/3(sin(2 - 3x)dx ⇒ -4/9cos(2 - 3x) + C
Combine:

Answer:
3(4a−5b+2)
Step-by-step explanation:
The answer should have originally been 3(4a-5b+2)
3(4a+5b+3)= 12a+15b+9 which is incorrect.
Jerrad has a 3-day vacation, Max has a 6-day vacation, and Wesley's vacation is 12 days
Easy! just compare then cross multiply 70:1 × 10:4 because you need to use the negative reciprocal of either one to create division with ratios/fractions
Answer: 400.3
Step-by-step explanation: